Well, this you can do easily yourself. And I expect your tutor thinks so as well.
Consider, that any number below 120 [well actually 124] that can be factored will have factors no larger than 12.
For a number less than or equal to 12 will be the highest common factor.
Good you're getting there!
So you can eliminate all the even numbers, and all the numbers ending in 0 or 5, for all those are obviously not prime.
Make a list of the numbers, and cross out all the evens, etc. as above.
You'll have about 60 + 24 (the 10s and 5s) = crossed out, so you have to examine the remainder, (~26 numbers) to consider. [Check the math there!!!]
And you'll only have to try them for division by up to 12.
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Here is the list:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113
Look up a list of prime numbers (a Google search for "prime numbers" or "list of prime numbers" should do); every number (greater than 1) that is NOT a prime number is composite.
Do you mean what is a list of prime numbers up to 11? If that is the question, the answer is 2, 3, 5, 7, 11. If you're asking for the prime factorization, it doesn't have one. 11 is already prime. The only prime factor of 11 is 11.
It is a prime number, because it has no factors. For numbers up to 120, it is enough to test whether the number is divisible by 2, 3, 5, and 7.
You start finding one factor. Divide by that factor, to get another factor. Continue looking for smaller factors, until you only have prime numbers. For numbers up to 120, it is enough to check the prime factors 2, 3, 5, and 7.
No, there are only 25 prime numbers less than 100.........remember that 1 is classed as unity and is not a prime number and 2 is the only even prime number.
Look up a list of prime numbers (a Google search for "prime numbers" or "list of prime numbers" should do); every number (greater than 1) that is NOT a prime number is composite.
2,3,5,7,11,13,17,19,23,29,31,37,39,41,43,47,51,53,57,59,61,67,71,73
Yes, 997 is a prime number.You can either work it out, or look it up in a list of prime numbers!For list of the first 1,000 prime numbers, see Related links below this box.
Please note that there are infinitely many prime numbers. An Internet search for "list of prime numbers" will quickly give you a list of prime numbers up to a certain point, for example here: http://en.wikipedia.org/wiki/List_of_prime_numbers Any integer greater than 1 that is not in the list of prime numbers is a composite number. (1 is considered neither a prime number, nor a composite number.)
That will be difficult to answer specifically without the list of numbers, but as a general rule, test up to the square root.
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
Prime numbers like counting numbers go tyo inifinity. However, here are the prime numbers up to '20'. 2,3,5,7,11,13,17,& 19.
Do you mean what is a list of prime numbers up to 11? If that is the question, the answer is 2, 3, 5, 7, 11. If you're asking for the prime factorization, it doesn't have one. 11 is already prime. The only prime factor of 11 is 11.
It is a prime number, because it has no factors. For numbers up to 120, it is enough to test whether the number is divisible by 2, 3, 5, and 7.
You start finding one factor. Divide by that factor, to get another factor. Continue looking for smaller factors, until you only have prime numbers. For numbers up to 120, it is enough to check the prime factors 2, 3, 5, and 7.
There are 15 prime numbers up to 50.
I suggest you try dividing it by different numbers, and see whether it is divisible. If you find a divisor, then it is composite. Otherwise it is a prime. For numbers up to 120, it is sufficient to test divisibility by 2, 3, 5, and 7.