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A man who is walking has a momentum of 80 kilogram meters per second west The man has a mass of 80 kilograms which is the velocity of the man?
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
What is the momentum of a 21 kg bicycle traveling west a 3.0 meters per second?
Momentum = m V = (21) x (3 west) = 63 kg-m/sec west(Bold italics are vectors)
An airplane flying from New York to Los Angeles is traveling at a velocity of 1400 kph west There is a head wind with a velocity of 20 kph east What is the resultant velocity of the airplane in kph?
1380 kph west
If Ben runs from a position 3 miles west of Main Street to a new position 45m west of Main Street in 6 seconds - What is Ben's velocity?
Velocity = distance divided by time / Velocity = average speed over time / Acceleration = (change of) velocity divided by time elapsed Change in velocity = final velocity "minus" initial velocity divided by time elapsed
A car travels west for 240km in 4h What is the cars velocity?
60km per hour west.
A man who is walking has a momentum of 80 kilogram meters per second west The man has a mass of 80 kilograms which is the velocity of the man?
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
A dog has a momentum of 60 kilogram meters per secound west the dog has a velocity of 3 meters per secound west what is the mass of the dog?
20 kilograms
A dog has a momentum of 60 kilogram meters per second west The dog has a velocity of 3 meters per second west What is the mass of the dog?
To find the mass of the dog, we can use the formula for momentum, which is momentum = mass × velocity. Given the momentum of 60 kg·m/s and a velocity of 3 m/s, we can rearrange the formula to find mass: mass = momentum / velocity. Thus, the mass of the dog is 60 kg·m/s ÷ 3 m/s = 20 kg.
If a bicycle has a mass of 10 kg and velocity of 11 ms to the west what is the magnitude of its momentum?
The magnitude of momentum is calculated as the product of an object's mass and velocity. In this case, the magnitude of the bicycle's momentum would be 110 kg*m/s to the west.
If a bicycle has a mass of ten kg and a velocity of eleven ms to the west what is the magnitude of its momentum?
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If a bicycle has a mass of 10 kg and a velocity of 11 ms to west what is the magnitude of its momentum?
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the momentum of the bicycle can be calculated as 10 kg * 11 m/s = 110 kg m/s.
If a bicycle has a mass of 10kg and a velocity 11ms to the west what is the magnitude of its momentum?
Momentum = Mass x Velocity = 11 x 10 = 110 Ns (Newton seconds)
What is the momentum of a 90 kg athlete running west at 3 m s?
Momentum = mass x velocity. Momentum = (90 kg) x (3 m/s) Momentum = 270 kgm/s
A person is riding a bike at 5 m's due west The mass of the rider plus bike is 95 kg What is the magnitude of its momentum?
Momentum = mass x velocity Assuming you mean the rider is riding at 5 m/s, the momentum is 95 x 5, which is 475 kg-m/s
What force acting for 0.025 seconds will change the velocity of a 100 gram baseball from 35 ms eastward to 20 ms westward?
The change in velocity is 35 m/s (east) - (-20 m/s) (west) = 55 m/s. The impulse required can be calculated as mass x change in velocity, which is 100 grams (0.1 kg) x 55 m/s = 5.5 Ns. The average force can be calculated as impulse / time, which is 5.5 Ns / 0.025 s = 220 N.
30mph west is an example of?
It is an example of a velocity.
What is the change in angular momentum of a planet with radius R if an asteroid mass m and speed v hits the equator at an angle from the West 40 degrees from the radial direction?
The asteroid's velocity component tangent to the surface of the planet at the equator is:│v│∙ sin 40oThis times the mass of the asteroid gives the impulse (F∙t) the asteroid gives tothe planet, tangent at the point of impact and in the direction of the planet rotation:m∙│v│∙ sin 40oThis time the radius of the planet gives the increment in angular momentum ofthe planet:R∙│v│∙ sin 40o
