1 meter per second west.
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
Momentum = m V = (21) x (3 west) = 63 kg-m/sec west(Bold italics are vectors)
1380 kph west
Velocity = distance divided by time / Velocity = average speed over time / Acceleration = (change of) velocity divided by time elapsed Change in velocity = final velocity "minus" initial velocity divided by time elapsed
60km per hour west.
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
20 kilograms
The magnitude of momentum is calculated as the product of an object's mass and velocity. In this case, the magnitude of the bicycle's momentum would be 110 kg*m/s to the west.
1
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the momentum of the bicycle can be calculated as 10 kg * 11 m/s = 110 kg m/s.
The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the magnitude of the momentum of the bicycle would be 110 kg*m/s.
The momentum of the athlete can be calculated using the formula: momentum = mass x velocity. Plugging in the values, we get momentum = 90 kg x 3 m/s = 270 kg m/s.
Momentum = mass x velocity Assuming you mean the rider is riding at 5 m/s, the momentum is 95 x 5, which is 475 kg-m/s
The change in velocity is 35 m/s (east) - (-20 m/s) (west) = 55 m/s. The impulse required can be calculated as mass x change in velocity, which is 100 grams (0.1 kg) x 55 m/s = 5.5 Ns. The average force can be calculated as impulse / time, which is 5.5 Ns / 0.025 s = 220 N.
It is an example of a velocity.
The asteroid's velocity component tangent to the surface of the planet at the equator is:│v│∙ sin 40oThis times the mass of the asteroid gives the impulse (F∙t) the asteroid gives tothe planet, tangent at the point of impact and in the direction of the planet rotation:m∙│v│∙ sin 40oThis time the radius of the planet gives the increment in angular momentum ofthe planet:R∙│v│∙ sin 40o
The resultant velocity is calculated by subtracting the headwind velocity from the airplane's velocity: 1400 kph (west) - 20 kph (east) = 1380 kph (west)