The volume of displaced water for a metal cylinder with a volume of 50cm3 is: 13,210 US gallons of water or 11,000 UK gallons of water.
The volume of any cylinder is (pi) x (radius of the circular end)2 x (length of the cylinder)
First of all, if you're going to work with the volume of displaced water, it makes no difference at all how much water you start out with. The object would displace the same amount from a bucket as it would from Lake Michigan. But, to deal with the answer to your question: It's not possible to answer your question. The volume of water displaced is the same as the volume of the metal that you drop into the bucket. But you've only told us the area of one flat side of the metal. We have no idea what its volume may be until we also know its thickness.
The volume of the piece of metal is measured by the difference in the volume of water in the graduated cylinder before and after the piece of metal is placed in the cylinder. This is stated to be 36 - 20 = 16 mL. Density is defined to be mass per unit volume. Therefore, for this piece of metal the density is 163/16 = 10 g/mL. (Only two significant digits are justified, because the is the number of significant digits in the limiting datum 16.)
Density = mass/volume = 167g/ (volume displaced) = 167g / (36mL - 20mL) = 167g/16mL = 10.4g/mL. Density is usually recorded in g/cm3 which is the same as g/mL so the density is 10.4g/cc. Also, to be extra correct, the answer should be rounded to 10g/cc because 16mL only has 2 significant figures so that is the number you report in your final answer.
There are several methods that can be used to calculate the density of a metal ball. The density of a metal ball can be derived from the fact that the volume is: 4*(pi)*r^3/3 and the denisty is mass/volume. If the mass and moment of inertia are known but the dimensions of the metal ball are not, then you can use the fact that the moment of inertia of the ball is 2m*r^2/5 and solve for m to get r=(5I/2)^.5 and plug in the value for r into the volume equation then calculate the density of the ball by dividing the mass by the calculated volume.
The volume of the metal can be calculated by measuring the volume of water displaced after the metal was placed in the cylinder. If the water level rose to the 25 cubic meter mark after the metal was added, then the volume of the metal is 5 cubic meters.
The increase in volume of the water when the cylinder is added is equal to the volume of the cylinder. So, the volume of the cylinder is 21.4 mL - 15 mL = 6.4 mL. Since the metal cylinder is immersed in water, the volume of the metal cylinder is 6.4 mL.
The reading on the graduated scale is taken before and after the metal is lowered into the cylinder . The second reading is subtracted from the first. This gives the volume of the metal in cubic centimetres.
The volume of any cylinder is (pi) x (radius of the circular end)2 x (length of the cylinder)
The volume of the metal sample can be calculated as the difference in the liquid level before and after adding the metal. In this case, the volume displaced by the metal is 7.5 ml. The density of the metal sample is then calculated by dividing the mass of the sample (37.51 g) by the volume displaced (7.5 ml), resulting in a density of 5.0 g/ml.
The metal block will displace a volume of water equal to its own volume. By measuring the volume of water displaced, you can then determine the mass of the metal block - as long as you know the density of water (1 gram per cubic centimeter).
You'd use a "Eureka can!" If you fill a cup or special container completely full and submerge the object you want to measure in the water then water will be displaced by the object. If you collect the water and measure it in a measuring cylinder then you will have the volume of water displaced, which will be exactly the volume of the object. The "Eureka can!" is named because of Archimedes discovery or displacement and density which allegedly caused him to run naked down the street shouting "Eureka" in celebration.
The first step is to calculate the volume of the metal using its density and mass. Volume = mass / density = 13.3543 g / 7.51 g/cm^3 = 1.779 cm^3. Therefore, 1.779 cm^3 of water would be displaced by the metal.
The density of the metal can be calculated by finding the mass of the metal and dividing it by the volume of water displaced. First, subtract the initial volume of water (15 ml) from the final volume (39.3 ml) to find the volume of water displaced (24.3 ml). Density = mass of metal (52.9 g) / volume of water displaced (24.3 ml). Calculate the density using these values.
First of all, if you're going to work with the volume of displaced water, it makes no difference at all how much water you start out with. The object would displace the same amount from a bucket as it would from Lake Michigan. But, to deal with the answer to your question: It's not possible to answer your question. The volume of water displaced is the same as the volume of the metal that you drop into the bucket. But you've only told us the area of one flat side of the metal. We have no idea what its volume may be until we also know its thickness.
1357.2
525/50 = 10.5 g/cm3