Let x = the numbernumber increased by 10 = x + 10
Let x equal the unknown number(3*x)+6 = -243x = -30x = -10
Let x be the unknown number. the expression is: x + 10.
01-x
let x be the number, then: (x + 1) × 2 + 5 = x + 1 → 2x + 2 + 5 = x + 1 → 2x + 7 = x + 1 → 2x - x = 1 - 7 → x = -6 The number is -6. Checking: -6 +1 = -5; 5 × 2 = -10; -10 + 5 = -5 which is the same as -6 + 1 = -5.
3x+30let x = "a number"(x+10) = "a number increased by 10"3(x+10) = "3 times a number increased by 10"Expand: 3x+30
Let x = the numbernumber increased by 10 = x + 10
Let x equal the unknown number(3*x)+6 = -243x = -30x = -10
01-x
Let x be the unknown number. the expression is: x + 10.
If the number is x then: 4x+10 = -2 and so the value of x is -3
x+8+x/5 = 20 x = 10
To determine the number of moles in 1.204 x 10^24 entities, you need to divide the given number by Avogadro's number, which is 6.022 x 10^23 entities/mol. Therefore, 1.204 x 10^24 entities divided by 6.022 x 10^23 entities/mol equals 2 moles. So, there are 2 moles in 1.204 x 10^24 entities.
let x be the number, then: (x + 1) × 2 + 5 = x + 1 → 2x + 2 + 5 = x + 1 → 2x + 7 = x + 1 → 2x - x = 1 - 7 → x = -6 The number is -6. Checking: -6 +1 = -5; 5 × 2 = -10; -10 + 5 = -5 which is the same as -6 + 1 = -5.
Let X be the number: (X * 3 / 7) + 14
To find the number of moles in 3.6 x 10^24 atoms of chromium, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol). 3.6 x 10^24 atoms of Cr / 6.022 x 10^23 atoms/mol ≈ 5.98 moles of Cr.
To calculate the number of moles, we divide the number of atoms by Avogadro's number, which is 6.022 x 10^23. In this case, 2.4 x 10^24 atoms of He divided by 6.022 x 10^23 atoms/mole is equal to approximately 4 moles of He.