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The perimeter of an octagon that has one side of 2 inches is 16 inches.
The perimeter is 40 meters.
152 inches
The perimeter would be (12 + 8) x 2 which is 40.
perimeter of a parallelogram = 2(w+h) where:w is the base length of the parallelogramh is the side lengthIf you know the length of one side, then the opposite side must have the same length.This is not enough information to fine the perimeter since you have only h or w and not both.
The perimeter is 40 meters.
The perimeter of an octagon that has one side of 2 inches is 16 inches.
40 m
The perimeter would be (12 + 8) x 2 which is 40.
152 inches
perimeter of a parallelogram = 2(w+h) where:w is the base length of the parallelogramh is the side lengthIf you know the length of one side, then the opposite side must have the same length.This is not enough information to fine the perimeter since you have only h or w and not both.
The answer is 166 inches.
The perimeter of a parallelogram is not enough to determine its length. Let 6 ≤ A < 12 units be the length of the parallelogram and let B = (12 - A) units be its breadth. Then the perimeter of the parallelogram will be 24 units. But A is any one of infinitely many values between 6 and 12. So the dimensions are indeterminate.
9 inches
24 inches
104 inches.
Length of one side = 114/6 inches = 19 inches