(a + b+ c)3 = a3 + b3 + c3 + 3a2b + 3ab2 + 3b2c + 3bc2 + 3c2a + 3ca2 + 6abc
Chat with our AI personalities
The cube of A plus B is either A**3 + B or (A + B)**3 depending on what you intended to be cubed.
a3+b3=(a+b)3-3a2b-3ab2
Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.