The cube of A plus B is either A**3 + B or (A + B)**3 depending on what you intended to be cubed.
a3+b3=(a+b)3-3a2b-3ab2
Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.
(a+b)cube = a cube + b cube + 3a square b + 3ab square
'a' minus 'b' whole cube is equal to 'a cube' minus 'b cube' minus (3 a square b ) plus (3 a b square) . .. .....thanks
(a + b)3 = a3 + 3a2b + 3ab2 + b3
Yes.
The cube of A plus B is either A**3 + B or (A + B)**3 depending on what you intended to be cubed.
a3+b3=(a+b)3-3a2b-3ab2
the answer is a
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.
This is the formula: (a3)+(b3)=(a+b)(a2-ab+b2)