The perimeter of a square with side 115 = 115 X 4 = 460.
A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.
23 is your answer.
The length of each side is (115 inches)/(the number of sides in the polygon) .
43,560 square feet = 1 acre(110' x 115') = 12,650 square feet = 0.29 acre (rounded number)
328 yards or 984 feet.
The perimeter of a square with side 115 = 115 X 4 = 460.
To solve this, start by calculating the perimeter of the soccer field. Then divide the number of yards in a mile (1760) by the number of yards in the perimeter to get your answer.
A room that is 25.5 yards * 32 yards has a perimeter of 2*(25.5 + 32) = 2*57.5 = 115 yards. If each string of lights is 5 yards long, the number of strings required is 115/5 = 23.
500 ft. tall and 30 ft. wide
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The perimeter of an octogon can be calculated by multiplying the length of one side by 8, so:Perimeter = side x 8 = 115 mm x 8 = 920 mm
920 mm. Because since an octagon has 8 sides and they are all 115 in length, to find the total perimeter simply add up 115 8 times, or multiply 115 by 8.
for a professional team its 115 yards long and 70 yards wide
23 is your answer.
The length of each side is (115 inches)/(the number of sides in the polygon) .
About 3 feet 9.28 inches wide.