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First, convert the courtyard into metres. This is simple. 18.72m by 13.20m.

Next, find the highest common denominator of 18.72m and 13.20m. This is 0.24m. The tiles will be 24cm^2.

The total number of tiles to cover the length is 78. Width, 55. Multiply these together to get the total tiles needed for the whole area; 4290.

Q: A rectangular court yard is 18m72cm long and 13m 20cm broad It is to be paved with square tiles of the same size Find the least possible number of such tiles?

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