If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
If the polygon has n sides, each exterior angle is 360/n degrees.The interior angle is 180 less exterior angle.
Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)
360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360
Not possible in this Universe. Smallest regular polygon is a triangle when interior angles are 60o. If exterior angles are 30o the polygon has 360/30 ie 12 sides.
A Regular Polygon
octagon interior=135 exterior=45
An equilateral triangle.
A quadrilateral.
Hint: in a regular polygon interior plus exterior = 180o, always.
The easiest way to solve this is to use the exterior angles of the polygon. The sum of an exterior angle and interior angle is 180o. Also the sum of all the exterior angles of a polygon is 360o. As the polygon is regular, all the interior angles are the same and all the exterior angles are the same. So, for an interior angle of 172o the exterior angle is 180-172 = 8o. The sum of all the exterior angles is 360o so how many 8o make up 360o? 360/8=45. Thus the polygon with interior angles of 172o has 45 sides.
Interior angles 178 so exterior angles 2. Number of sides of any regular polygon = 360/exterior angle You polygon has 180 sides. Bet you're glad you didn't have to sketch it!
Exterior angles are supplementary with interior angles, so 180-30=150
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
hexagon
4 such as a square
If the polygon has n sides, each exterior angle is 360/n degrees.The interior angle is 180 less exterior angle.