Q: A segment has endpoints -9 -20 and 14 12 What is the midpoint of this segment?

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End points: (14, 7) and (6, 7) Midpoint: (10, 7)

There are only three endpoint given and these are not sufficient to define a segment of a line.

Points: (-2, -4) and (4, -14) Midpoint: (1, -9)

To find the coordinate for the midpoint, divide the differences in the X and Y positions by 2 and add to the lesser or subtract from the greater coordinate (the result has to be in between)X: from -9 to 5 is 14 units 14/2 =7-9 + 7 = -2Y: from 8 to -2 is 10 units 10/2 = 5-2 + 5 = 3The midpoint of AB is {-2;3}

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Related questions

End points: (14, 7) and (6, 7) Midpoint: (10, 7)

There are only three endpoint given and these are not sufficient to define a segment of a line.

Points: (-4, -14) and (-22, 9) Midpoint: (-4-22)/2, (-14+9)/2 => (-13, -2.5)

Points: (-2, -4) and (4, -14) Midpoint: (1, -9)

14

The midpoint of the teenage years would be 15 or 16. That way, 12 to 14 is earlier, and 17 to 19 is later. It is symmetrical.

You will need endpoints of your range (for example age: 12-14, 15-17. The endpoints are 14 and 17). You will also need the cumulative total of the relative frequencies (add all relative frequencies). -To find the relative frequency = value over total (ex, age 12-14, 51 have diabetes, 90 do not. The total of those having diabetes is 3800. So for the relative frequency of ages 12-14, it is 51/3800=0.01342. Do this for all ranges). -To find the Cumulative Frequency: add all these frequencies (separate for "yes" diabetes and "no" diabetes). Use endpoints of your range for the x-axis (horizontal axis). Then use the cumulative frequencies as your y-axis (vertical axis).

Midpoint: (2, -9)

Half of XY...

THE point L(2,-1),M(-1,4) and N(-2,2)are the midpoint of the sides of a triangle .find its vertices?

THE point L(2,-1),M(-1,4) and N(-2,2)are the midpoint of the sides of a triangle .find its vertices?

To find the coordinate for the midpoint, divide the differences in the X and Y positions by 2 and add to the lesser or subtract from the greater coordinate (the result has to be in between)X: from -9 to 5 is 14 units 14/2 =7-9 + 7 = -2Y: from 8 to -2 is 10 units 10/2 = 5-2 + 5 = 3The midpoint of AB is {-2;3}