A 6-sided die has 6 possible outcomes. If each of the sides has a different number from 1 to 6, then the probability of getting any one number is 1/6 or 16.67%.
The probability of heads is 1/2.
To find the probability of getting at least one head in 4 coin tosses, it's easier to calculate the complementary probability of getting no heads at all (i.e., getting all tails). The probability of getting tails in a single toss is 0.5, so for 4 tosses, the probability of all tails is ( (0.5)^4 = 0.0625 ). Therefore, the probability of getting at least one head is ( 1 - 0.0625 = 0.9375 ) or 93.75%.
1 out of 16
Since each event is independent, the probability remains at 0.5.
If you toss them enough times, the probability is 1. For just one toss the probability is 1/4.
total outcome in single toss={H,T} u want 1 head probability of getting 1 head= 1/2=0.5
The probability of heads is 1/2.
A 6-sided die has 6 possible outcomes. If each of the sides has a different number, one through six, then the probability of getting any one number is 1/6.
The probability is still 50%
Probability = 0.5
If you toss the coins once only, it is 1/4.
1 in 2 to get tails on first toss 1 in 2 to get heads on second toss To get tails on first toss and heads on second toss, probability is 1/2 x 1/2 = 1 in 4
1/6 * 1/2 = 1/12
The probability of getting a head is 1/2 and if you toss it 4 times, the probability of 4 heads is (1/2)^4=1/16 since the tosses are independent events.
In a single toss? zero. In two tosses, well that's a different question. Possible combinations are TT, HT, TH and HH, of which 2 of the 4 are one head and one tail. So probability is 0.50 in two tosses.
1:4
50% or 5