volume of spherical = 4/3*Pi*Radius^3 = 4/3*3.14*32^3=137188
It is the distance from the centre to all points on the surface of a sphere with a radius of 1 foot.
The radius of curvature of a spherical surface is the radius of the sphere from which the surface is derived. It is defined as the distance from the center of the sphere to the surface at any point. For a perfect sphere, the radius of curvature is constant and equal to the sphere's radius. This concept is crucial in optics and geometry, as it helps determine how light rays behave when they encounter curved surfaces.
i need the height dude what is the height?
Balls can be spherical or not. The (American) football uses a ball that is far from spherical. However, a sphere is a perfect geometrical solid with a uniform radius, and a ball made in that shape is quite suitable for games. It will, for instance, bounce in a predictable way.
volume of spherical = 4/3*Pi*Radius^3 = 4/3*3.14*32^3=137188
Radius is a sensible measure to use with a circular (or spherical) shape. England is neither.
The uncertainty in radius is approx 5.95%.
It is the distance from the centre to all points on the surface of a sphere with a radius of 1 foot.
It's about 2440 kilometers. Mercury is almost spherical, so the radius is about the same everywhere.
Yes
You can measure the diameter, then divide that by 2.
Volume of the sphere varies as the cube of the radius.Tripling the radius increases the volume by a factor of (3)3 = 27.It takes 27 spherical volumes with radius 'r' to fill one spherical volume with radius '3r'.
The radius of curvature of a spherical surface is the radius of the sphere from which the surface is derived. It is defined as the distance from the center of the sphere to the surface at any point. For a perfect sphere, the radius of curvature is constant and equal to the sphere's radius. This concept is crucial in optics and geometry, as it helps determine how light rays behave when they encounter curved surfaces.
Its radius of curvature and its reflecting property
By increasing its radius of curvature to infinity.
No, it would not, because the smallest possible radius for a spherical celestial body is 200 km (124 miles) and Mercury would only have a radius of 61 miles (98 km) if it was shrunk 96%.