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x=1/2at2 and

a=9.81m/s2 so

2.88m = 4.905t2

t = 0.77 s

v=at so

v= 7.5 m/s

momentum = mv = (m)kg* 7.5m/s = 7.5m

Now with a mass of m/2 having a momentum of 7.5m we have to double the velocity.

7.5m = 7.5(m/2)*2 = 15m

To get a velocity of 15m/s

15m/s = at so t= 1.53 s

distance is x=1/2at2

x=1/2at2 x= 11.48m

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