x=1/2at2 and
a=9.81m/s2 so
2.88m = 4.905t2
t = 0.77 s
v=at so
v= 7.5 m/s
momentum = mv = (m)kg* 7.5m/s = 7.5m
Now with a mass of m/2 having a momentum of 7.5m we have to double the velocity.
7.5m = 7.5(m/2)*2 = 15m
To get a velocity of 15m/s
15m/s = at so t= 1.53 s
distance is x=1/2at2
x=1/2at2 x= 11.48m
It depends on what percent it was dropped.
Einstein dropped out of school when he was 16 in Munich, Germany.
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.
1050 is the four digit number don't know which mathematical procedure to use it took me 5 mins to make a small C# program and ta-da! that's it. :)) cheers
Acceleration = (change in speed) divided by (time for the change)= (4.9) / 3 = 1.63 m/s2(rounded)
No, two falling bodies of different masses cannot have the same momentum just before striking the ground unless they are falling under the same gravitational conditions. Momentum is a product of mass and velocity, so for two bodies with different masses to have the same momentum, their velocities would also have to be the same.
8.83 kg-m/s
It has more momentum from a higher height. Because momentum is always conserved, and momentum is the product of mass times velocity, more sand particles must move away faster in order to conserve the momentum of a heavy ball moving fast. The ball is moving faster from a higher height because the acceleration due to gravity (-9.81 m/s^2) increases the velocity of a falling object after each second its been falling.
When a ball is dropped and bounces back to its original height, it is experiencing an elastic collision with the ground. In an elastic collision, both kinetic energy and momentum are conserved.
When a metal and a plastic ball are dropped from the same height, they will both experience the same change in potential energy, leading to the same kinetic energy at the bottom. However, the two balls may not have the same momentum at the end due to differences in mass and velocity.
Ignoring air resistance (which probably is not safe to do) it would impact at a smidge over 18 seconds from when it was released and be traveling about 580 feet per second.
The initial momentum of the railroad car is 120,000 kgm/s (20,000 kg * 6 m/s). When the 8000 kg load of gravel is dropped in, the total momentum is conserved. Therefore, the final speed of the railroad car can be calculated by dividing the total momentum (120,000 kgm/s) by the new total mass (28,000 kg). This gives a final speed of 4.29 m/s.
It really doesn't. What happens is that the bomb explodes on impact and the momentum causes the fluid to continue moving along the line of motion.
The knowledge of the process to create sparks, and thus start a fire, by striking two stones together is very ancient and was probably discovered by observation of the accident of one dropped stone striking another and throwing a spark. It was probably discovered at different times and in different places. The name of anyone who made that discovery a long lost in the mists of time.
12 did not break. (24 divided by 2 = 12)
Yes, objects dropped from a greater distance will hit the ground with a greater force due to the additional time they have to accelerate toward the Earth's surface. The force of gravity causes objects to accelerate as they fall, and this acceleration increases the speed and impact force of the object when it reaches the ground.
mass x velocity = momentum