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Q: A tetrahedral die has 4 triangular sides numbered 1 to4 If two tetrahedral dice are rolled what is the probability the sum is 7?

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Even if I assume that you mean probability and not probility, the question cannot be answered since there is no information as to what is being rolled. For a normal tetrahedral die, the answer is 1.

Even if I assume that you mean probability and not probility, the question cannot be answered since there is no information as to what is being rolled. For a normal tetrahedral die, the answer is 1.

The probability of drawing the 10 is 1/10 and the probability of rolling a 3 is 1/6. So, the probability of both is 1/10 * 1/6 = 1/60.

The probability is 1, if the dice are rolled often enough.

the probability is 1 out of 6

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Even if I assume that you mean probability and not probility, the question cannot be answered since there is no information as to what is being rolled. For a normal tetrahedral die, the answer is 1.

When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.

The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.

The probability is 0.277... (repeating).

7

The probability of drawing the 10 is 1/10 and the probability of rolling a 3 is 1/6. So, the probability of both is 1/10 * 1/6 = 1/60.

The probability is 1, if the dice are rolled often enough.

the probability is 1 out of 6

It can roll on 1,2,3,4,5,6 so the probability of 2/6 is ±33.33%

If it is a fair die that is rolled once, then the probability is 2/3.

It is 1/9.

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