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distance = rate * time

1st leg: d=r*7

2nd leg: d=(r+12)*5

7r=5r+60

2r=60

r=30 km/hr

d=30*7=210 km

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Q: A train travels a certain distance taking seven hours in forward journeyduring the return journey increased speed twelve km per hrs takes the time five hrswhat is the distance traveled?
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