A.120 metres
B.180 metres
C.324 metres
D.150 metres
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Frequency (1/seconds) x Wave Length (meters) = Speed (meters/sec. or m/s)
Please use the formula: distance = speed x time If you have length in miles and speed in miles per hour, if you solve for time you will get the time in hours. You can then convert that to seconds.
s=d/ts= 100 / 12s= 8.33ms-1
Leg length can affect running speed by influencing stride length, which is the distance covered with each step. Longer legs can potentially lead to a longer stride length, allowing for greater speed. However, factors such as stride frequency, muscle strength, and technique also play important roles in determining running speed.
The answer is 72Km/hr
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
Assume Length of the train =x metre,speed be y metre/ sec Time taken to cross the pole x/y sec Time taken to cross the platform=length of train+length of platform/ speed of train x/y=15 x=15y x+100/y=25 15y+100=25y 10y=100 Y=10 metre/ sec x=15y = 100
Simply horse racing is the sport of running horses at speed and the one who crosses the finishing post first is the winner.
Simply horse racing is the sport of running horses at speed and the one who crosses the finishing post first is the winner.
11.875 m/s
To calculate the speed of the elk, you would use the formula: speed = distance/time. In this case, the distance covered is 100 meters and the time taken is 5 seconds. So, the speed of the elk would be 100 meters / 5 seconds = 20 meters per second. Therefore, the elk is running at a speed of 20 meters per second.
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Since length is measured in meters, and time in seconds, it follows that speed is measured in meters/second.
200m. Here's the work:The speed of the train in meters per second is:(36km/hr)(1000m/km) / (3600s/hr) = 10 m/sIf it takes 80 seconds to cross, then the distance traveled in 80s at 10m/s is:(10m/s)(80s) = 800mNow, imagine this:The front end of the train travels 800 meters from the time it reaches the bridge until the back end is clear of the bridge. This means that the length of the train equals the distance traveled minus the length of the bridge.So:800m - 600m = 200mThe train is 200m long.
The average speed of the runner is 1500m/(180 + 49.67) seconds = 6.531 m/s or 13 knots.