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Rise over run or y over x.
slope is change in y over change in x
Each lane is 0.9144 m wide. For one lap of the 200 m track, the distance increase per lane is 0.9144 x 2(pi) = 5.745 m Lane 1 on the start line. Lane 2 at 5.75 m Lane 3 at 11.5 m Lane 4 at 17.25 Lane 5 at 23 m
The solution to the proportion 8 over x 5 over 10 is that x is 16.
If: x/(13-x) = 2/3 Then: x = 5.2