92 x 4 = 368 368 + 85 = 453 453/5 = 90.6 is your average for all 5 tests
Simi's tests so far can be expressed as 320 percent divided by four. To average 84 percent, she would need five times 84 or 420 percent. The difference is 100%. Assuming all the tests are equally weighted, she needs 100% on the 5th test.
(81 + 77 + 83 + 75 + X) divided by 5 = 80 average 316 + X = 400 X = 84
There are different possible ways: - Eight four point four five five - Eighty-four point four five five - Eighty-four and four hundred fifty-five thousandths.
I'll bite: False. Four is four-fifths of five.
You take four thousand one hundred twenty average. by sayid and ahmed
78
Simi's tests so far can be expressed as 320 percent divided by four. To average 84 percent, she would need five times 84 or 420 percent. The difference is 100%. Assuming all the tests are equally weighted, she needs 100% on the 5th test.
The arithmetic mean is 79.
To find the lowest possible score Alicia could have earned on one test, we can set up an equation. Since her average score is 88 points for all five tests, the total points she earned on all five tests is 5 * 88 = 440 points. If we assume the lowest score on one test is x, then the total points earned on the other four tests would be 440 - x. Since the score range for each test is 0 to 100 points, the lowest possible score Alicia could have earned on one test is 0 points.
(81 + 77 + 83 + 75 + X) divided by 5 = 80 average 316 + X = 400 X = 84
Four to five feet.
No one has yet scored six, but four players have each scored five: Andy Cole, Alan Shearer, Jermain Defoe and Dimitar Berbatov.
99.94. He needed four, just four, runs in his last ever Test innings to end with an average of over 100, but he was out for 0.
A four to five member family.
between four feet and nine inches & five feet and four inches
Four to five years on average.
Gavaskar scored double centuries in tests four times . They are as :220 vs west indies205 vs west indies221 vs west indies236 vs west indies