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What else can I help you with?
After determining if two quantities are in inverse or direct you can find the equation's constant by solving for it?
variation
In the equation y15x what is the constant of variation?
It is 15.
After you have determined if two quantities are in direct or inverse variation the equation's can be solved for?
If you have already determined whether your particular model is direct or inverse variation, then the two models will follow the following functions: Direct: y=kx ---y is always expressible as a constant multiple of x, meaning it varies directly with x by a factor of k Inverse: y=k/x ---y is always expressible as a constant multiple of the inverse of x (1/x). It varies directly with the inverse of x by a factor of k.
Is the problem y equals 3x a direct variation if so what is the constant of variation?
y=3x is a direct variation in that y varies directly with x by a factor of 3. Any linear equation (a polynomial of degree 1, which is a polynomial equation with a highest exponent of 1), is a direct variation of y to x by some constant, and this constant is simply the coefficient of the "x" term. Other examples: y=(1/2)x is a direct variation, and the constant of variation is 1/2 y=-9x is a direct variation, and the constant of variation is -9
What is the compares in constant and variable rate of change?
Tell whether the equation -4x+ 2y = -2 represents a direct variation. If so, identify the constant of variation.
After determining if two quantities are in inverse or direct you can find the equation's constant by solving for it?
variation
What is constant of variation in math?
an equation of the form y = kx k is the constant of variation
In the equation y15x what is the constant of variation?
It is 15.
What is the equation of an inverse relationship?
The equation is xy = k where k is the constant of variation. It can also be expressed y = k over x where k is the constant of variation.
Find the constant variation k for the inverse variation then write an equation for the inverse variation y 2.5 when x 9?
The equation is xy = 22.5
After you have determined if two quantities are in direct or inverse variation the equation's can be solved for?
If you have already determined whether your particular model is direct or inverse variation, then the two models will follow the following functions: Direct: y=kx ---y is always expressible as a constant multiple of x, meaning it varies directly with x by a factor of k Inverse: y=k/x ---y is always expressible as a constant multiple of the inverse of x (1/x). It varies directly with the inverse of x by a factor of k.
Is the problem y equals 3x a direct variation if so what is the constant of variation?
y=3x is a direct variation in that y varies directly with x by a factor of 3. Any linear equation (a polynomial of degree 1, which is a polynomial equation with a highest exponent of 1), is a direct variation of y to x by some constant, and this constant is simply the coefficient of the "x" term. Other examples: y=(1/2)x is a direct variation, and the constant of variation is 1/2 y=-9x is a direct variation, and the constant of variation is -9
What is the compares in constant and variable rate of change?
Tell whether the equation -4x+ 2y = -2 represents a direct variation. If so, identify the constant of variation.
How do you find the constant and slope for direct variation equations?
For a direct variation equation the constant MUST be 0. Then the ratio of a pair of values of the two variables is the slope.
Is the equation Y MX B a constant of variation?
No, it is a linear equation which does not pass through the origin unless B = 0. If B = 0 then Y and X could be said to vary in direct proportion and M would be the constant of variation, not the whole equation.
Are constant variables and derived variables the same?
Constant variables are constant, they do not change. Derived variables are not constant. They are determined by the other values in the equation.
What is direct variation equation?
y = kx, where k is a constant, and x and y are the two variables.
