Lxi h,xx50
mov a,m
inx h
mov b,m
mvi ,ffh
inr c
sub b
jnc xx08
add b
inx h
mov m,c
inx h
mov m,a
hlt
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16 (48-bit) subkey are derived from the main key using key schedule.
The most significant difference between the Intel 8085 and 8086 microprocessors is that the 8085 is an 8-bit system and the 8086 is a 16-bit system. This difference allows the 8086 system to have a much larger set of operational instructions and can make calculations to more significant places. Note: the 8085 processor does have two 16-bit registers. The pointer and the program counter.
AND it to 1 and test for zero. All even numbers have 0 in the last bit.
If you're using C, just check the low order bit. In binary, the low order bit of an odd number is 1, and the low order bit of an even number is 0.
The 8085 is an 8-bit computer, with only limited capability to do 16 bit arithmetic. In order to add two 16-bit numbers, NUM1 and NUM2, together, and store the result at NUM3, you can use the code... LHLD NUM1 XCHG LHLD NUM2 DAD D SHLD NUM3 If you want to subtract NUM1 from NUM2, you need to take the two's complement first, by inverting it and adding one... LHLD NUM1 MOV A,H CMA MOV H,A MOV A,L CMA MOV L,A INX H ... and then continue with adding NUM2... XCHG LHLD NUM2 DAD D SHLD NUM3