an angle that is 54 degrees less than 4 times its complement
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
118 degrees is your answer... I am the type of person that just answers it without an explanation.
Suppose the angle is x degrees. Then (180 - x) = 4*(90 - x) 180 - x = 360 - 4x 3x = 180 so x = 60 degrees.
180 - x = 3(90 -x) 180 - x = 270 - 3x 3x - x = 270 - 180 2x = 90 x = 45 The angle is 45 degrees (complement is 45, supplement is 135).
15 degrees
The angle= 36, the supplement= 144, the compliment=54
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
25
118 degrees is your answer... I am the type of person that just answers it without an explanation.
74
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Nine degrees. Its supplement 171 degrees is ninteen times 9 degrees.
60 degrees.
Suppose the angle is x degrees. Then (180 - x) = 4*(90 - x) 180 - x = 360 - 4x 3x = 180 so x = 60 degrees.
67.5 degrees
180-20=160
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.