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An object in equilibrium has three forces exerted on it a 33-n force acts at 90 degrees from the x-axis and a 44-N force acts at 60 degrees What are the magnitude and direction of the third force?
Wiki User
∙ 11y ago
-- The sum of the two given forces is
44cos(60) in the x-direction
33 + 44sin(60) in the y-direction.
-- The components of the third force must be
-44cos(60) in the x-direction
-33 - 44sin(60) in the y-direction
-- The magnitude2 of the unknown force is
[-44cos(60)]2 + [-33 - 44sin(60)]2 = (484) + (5,055.94) = 5539.94
Magnitude = 74.43 newtons.
-- The angle of the third force is
tan-1 [-33-44sin(60)/-44cos(60)] = tan-1 (3.232) into the 3rd Quadrant = 72.8+180 = 252.8° .
Wiki User
∙ 11y ago
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