3 plus 3 plus 3 is 9. 3 plus 3 plus 3 plus 3 plus 3 plus 3 is 18.
The answer to your question is twenty four.
15
25
19 is the answer to 3 plus 4 plus 4 plus 3 plus 5
The chemical reaction is:AgNO3 + NaCl= AgCl + NaNO3The mass of products depends on the mass of reactants.
The oxidation number of hydrogen in NH3 is +1, and the oxidation number of nitrogen is -3. This is because hydrogen typically has an oxidation number of +1 and in compounds, nitrogen usually has an oxidation number of -3.
2 NH3 + 3 O2 = N2O3 + 3H2O
The coefficient is 1 for nitrogen and 3 for fluorine in the balanced equation for the reaction between nitrogen trifluoride (NF3) and nitrogen (N2) to form nitrogen gas (N2) and fluorine gas (F2). The symbol for this reaction is: 2 NF3 + N2 -> 3 F2 + 2 N2
The oxidation state of nitrogen (N) in NH4+ is -3. Nitrogen usually has a -3 oxidation state in ammonium ion (NH4+) as hydrogen is typically considered to have +1 oxidation state and there are four hydrogen atoms bonded to nitrogen in NH4+.
To find the valency of nitrogen in NH4+, you need to consider the overall charge of the ammonium ion, which is +1. Since there are four hydrogen atoms each with a valency of +1, the nitrogen atom must have a valency of -3 to balance out the charge of +1 on the ion. Therefore, the valency of nitrogen in NH4+ is -3.
27x3+6=87.
3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 plus 3 is 54.
There are a total of 3 nitrogen atoms in the formula Al(NO3)3.
3 plus 3 plus 3 is 9. 3 plus 3 plus 3 plus 3 plus 3 plus 3 is 18.
The balanced chemical equation for the decomposition of nitrogen trifluoride (NF3) is 2NF3 → N2 + 3F2. This reaction involves breaking down NF3 into nitrogen gas (N2) and fluorine gas (F2) through decomposition.
Iron + Nitric acid ----> Iron(III) nitrate + Water + Nitrogen Dioxide Fe + HNO3 ----> Fe(NO3)3 + H2O + NO2 NOTE: Nitrogen dioxide will come out only if the acid is concentrated. If it is dilute, Nitrogen monoxide will be produced.