Yes.
no
No. Most squares probably are not congruent. Although they are similar.
Since the opposite sides are congruent: perimeter = 2(2) + 2(3) = 10
A square 4 squares in the middle and 4 lines out so it has to be a square!!! actually a square does not have the same perimeter and area a 4x4 area square has 8 perimeter so no squares do not but i have made a shape that has 32 perimeter and 32 area so it is possible and we don't want to tell you what the shape is. i already gave you too much information with the 32.... << inccorect A 4x4 square does have the same perimeter and area 4x4=16 4+4+4+4=16 But there are also other shapes such as a circle witha diameter of 2 A right angled triangle with sides of 6, and 8 and the hypotenuse being 10 has the same area as perimeter.
Yes.
no
No. Most squares probably are not congruent. Although they are similar.
Squares and Rhombuses
Since the opposite sides are congruent: perimeter = 2(2) + 2(3) = 10
Every rectangle has. (That includes squares.)
No, because even through they have the same perimeter you must show how you can get 16 as the perimeter in two different ways.
Answer: Yes. A polygon can have the same perimeter length but smaller area than another polygon. Answer: For congruent or similar shapes, no. For different shapes, yes. Consider, for example, a rectangle 3 x 1, and another rectangle 2 x 2. They have different areas, but the same perimeter.
Yes, every square is congruent
no its an emphatic statement all squares can be cut in half to make 2 congruent isosceles right triangles is perhaps as general a statement as is possible
2 circles can be congruent. The have to have the same radius.
The easiest way to reason this is to consider how you could connect nine squares together while leaving the largest amount of perimeter exposed. In other words, what's the largest number of faces you can leave exposed on a set of squares that are all connected? The answer is that if you connect all of the squares in a line, then the two end squares will have three faces exposed and the other seven squares will have two faces exposed. That gives you 2 * 7 * 2cm + 3 * 2 * 2cm = 28cm + 12cm = 40cm. So the maximum perimeter you can get is 40cm. There are many other ways that you can arrange the squares to give you the same perimeter (eg. a plus sign, a zig-zag, and so on), but none that will give you more.