If you mean for collecting purposes, it would depend on the age, the mint markings and the condition. Otherwise, 37 quarters is $9.25 and 186 nickels is $9.30, so the nickels would be preferable by 5¢.
To make 37 cents with coins, you can use a combination of pennies, nickels, dimes, and quarters. The possible combinations include: 37 pennies, 1 quarter and 1 dime, 1 quarter and 3 nickels, 1 quarter, 1 dime, and 2 pennies, 3 dimes and 1 nickel, or 7 nickels and 2 pennies. In total, there are 5 ways to make 37 cents using different coin combinations.
37 cents7 nickels x 5 cents per nickle = 352 pennies x 1 cent per penny = 235 + 2 = 37
there are 23 quarters 37 dimes to do this use simultaneous equations to make this simpler i will assign variables to amount of quarters and dimes x-quarters y-dimes you know you have 60 coins, so amount of quarters plus dimes is 60 x+y=60 you also know the amount is equal to $9.45 since quarters are $0.25 and dimes are $0.10 another equation can be made 0.25x+0.10y=9.45 this equation shows what you do when you count your change now solve the first equation for a variable using algebra x=60-y you can then plug this new value into your second equation 0.25(60-y)+0.1y=9.45 you can now solve for y, which is the number of dimes y=37 now plug this number back into x=60-y to get the amount of quarters x=60-(37) x=23 23 quarters 37 dimes
Depends on your definition of "Sets of Coins"if this means combinations of units of currency the answer is Two (2):1) 6 quarters = 1.502) 5 quarters, 2 dimes, and 1 nickel = 1.50if each individual coin is treated as a unique item then option 2 becomes 36 different options:6 different quarters could be excluded3 different dimes could be excluded2 different nickels could be excludedfor 6x3x2 = 36 combinations +1 (the 6 quarter method)=37 sets of coins.
If you mean for collecting purposes, it would depend on the age, the mint markings and the condition. Otherwise, 37 quarters is $9.25 and 186 nickels is $9.30, so the nickels would be preferable by 5¢.
1.85
To make 37 cents with coins, you can use a combination of pennies, nickels, dimes, and quarters. The possible combinations include: 37 pennies, 1 quarter and 1 dime, 1 quarter and 3 nickels, 1 quarter, 1 dime, and 2 pennies, 3 dimes and 1 nickel, or 7 nickels and 2 pennies. In total, there are 5 ways to make 37 cents using different coin combinations.
There are 40 different ways to make a dollar without a single penny. 1. 2 half dollars 2. 1 half dollar 2 quarters 3. 1 half dollar 1 quarter 2 dimes 1 nickel 4. 1 half dollar 1 quarter 1 dime 3 nickels 5. 1 half dollar 1 quarter 5 nickels 6. 1 half dollar 5 dimes 7. 1 half dollar 4 dimes 2 nickels 8. 1 half dollar 3 dimes 4 nickels 9. 1 half dollar 2 dimes 6 nickels 10. 1 half dollar 1 dime 8 nickels 11. 1 half dollar 10 nickels 12. 4 quarters 13. 3 quarters 2 dimes 1 nickel 14. 3 quarters 1 dime 3 nickels 15. 3 quarters 5 nickels 16. 2 quarters 5 dimes 17. 2 quarters 4 dimes 2 nickels 18. 2 quarters 3 dimes 4 nickels 19. 2 quarters 2 dimes 6 nickels 20. 2 quarters 1 dime 8 nickels 21. 2 quarters 10 nickels 22. 1 quarter 7 dimes 1 nickel 23. 1 quarter 6 dimes 3 nickels 24. 1 quarter 5 dimes 5 nickels 25. 1 quarter 4 dimes 7 nickels 26. 1 quarter 3 dimes 9 nickels 27. 1 quarter 2 dimes 11 nickels 28. 1 quarter 1 dime 13 nickels 29. 1 quarter 15 nickels 30. 10 dimes 31. 9 dimes 2 nickels 32. 8 dimes 4 nickels 33. 7 dimes 6 nickels 34. 6 dimes 8 nickels 35. 5 dimes 10 nickels 36. 4 dimes 12 nickels 37. 3 dimes 14 nickels 38. 2 dimes 16 nickels 39. 1 dime 18 nickels 40. 20 nickels
1. 4 quarters 2. 3 quarters, 2 dimes, 1 nickel 3. 3 quarters, 2 dimes, 5 pennies 4. 3 quarters, 1 dime, 3 nickels 5. 3 quarters, 1 dime, 2 nickels, 5 pennies 6. 3 quarters, 5 nickels 7. 3 quarters, 4 nickels, 5 pennies 8. 2 quarters, 5 dimes 9. 2 quarters, 4 dimes, 2 nickels 10. 2 quarters, 4 dimes, 1 nickel, 5 pennies 11. 2 quarters, 3 dimes, 4 nickels 12. 2 quarters, 3 dimes, 3 nickels, 5 pennies 13. 2 quarters, 2 dimes, 6 nickels 14. 2 quarters, 2 dimes, 5 nickels, 5 pennies 15. 2 quarters, 1 dime, 8 nickels 16. 2 quarters, 10 nickels 17. 1 quarter, 7 dimes, 1 nickel 18. 1 quarter, 7 dimes, 5 pennies 19. 1 quarter, 6 dimes, 3 nickels 20. 1 quarter, 6 dimes, 2 nickels, 5 pennies 21. 1 quarter, 5 dimes, 5 nickels 22. 1 quarter, 4 dimes, 7 nickels 23. 1 quarter, 3 dimes, 9 nickels 24. 1 quarter, 2 dimes, 11 nickels 25. 10 dimes 26. 9 dimes, 2 nickels 27. 9 dimes, 1 nickel, 5 pennies 28. 8 dimes, 4 nickels 29. 7 dimes, 6 nickels 30. 6 dimes, 8 nickels 1. 31. 1 half dollar, 5 dimes 32. 1 half dollar, 4 dimes, 2 nickels 33. 1 half dollar, 4 dimes, 1 nickel, 5 pennies 34. 1 half dollar, 3 dimes, 4 nickels 35. 1 half dollar, 3 dimes, 3 nickels, 5 pennies 36. 1 half dollar, 2 dimes, 6 nickels 37. 1 half dollar, 2 dimes, 5 nickels, 5 pennies 38. 1 half dollar, 1 dime, 8 nickels 39. 1 half dollar, 10 nickels 40. 1 half dollar, 4 dimes, 10 pennies 41. 1 half dollar, 1 quarter, 2 dimes, 1 nickel 42. 1 half dollar, 1 quarter, 2 dimes, 5 pennies 43. 1 half dollar, 1 quarter, 1 dime, 3 nickels 44. 1 half dollar, 1 quarter, 1 dime, 2 nickels, 5 pennies 45. 1 half dollar, 1 quarter, 5 nickels 46. 1 half dollar, 1 quarter, 4 nickels, 5 pennies 47. 1 half dollar, 2 quarters 48. 2 half dollars Pretty sure that covers it, so there are 30 ways to make a dollar with less than 15 coins. At least 48 combinations if one does not omit a fifty cent piece!
37/93
37 cents7 nickels x 5 cents per nickle = 352 pennies x 1 cent per penny = 235 + 2 = 37
37 = 37. No other number (prime number or otherwise) is equal to 37.
Do that math yourself lazy!
there are 23 quarters 37 dimes to do this use simultaneous equations to make this simpler i will assign variables to amount of quarters and dimes x-quarters y-dimes you know you have 60 coins, so amount of quarters plus dimes is 60 x+y=60 you also know the amount is equal to $9.45 since quarters are $0.25 and dimes are $0.10 another equation can be made 0.25x+0.10y=9.45 this equation shows what you do when you count your change now solve the first equation for a variable using algebra x=60-y you can then plug this new value into your second equation 0.25(60-y)+0.1y=9.45 you can now solve for y, which is the number of dimes y=37 now plug this number back into x=60-y to get the amount of quarters x=60-(37) x=23 23 quarters 37 dimes
37% = 37/100
Depends on your definition of "Sets of Coins"if this means combinations of units of currency the answer is Two (2):1) 6 quarters = 1.502) 5 quarters, 2 dimes, and 1 nickel = 1.50if each individual coin is treated as a unique item then option 2 becomes 36 different options:6 different quarters could be excluded3 different dimes could be excluded2 different nickels could be excludedfor 6x3x2 = 36 combinations +1 (the 6 quarter method)=37 sets of coins.