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Would you rather have 37 quarters or 186 nickels?
If you mean for collecting purposes, it would depend on the age, the mint markings and the condition. Otherwise, 37 quarters is $9.25 and 186 nickels is $9.30, so the nickels would be preferable by 5¢.
What is 7 nickels 2 pennies?
37 cents7 nickels x 5 cents per nickle = 352 pennies x 1 cent per penny = 235 + 2 = 37
How many ways can you make 37 cents with coins?
To make 37 cents with coins, you can use a combination of pennies, nickels, dimes, and quarters. The possible combinations include: 37 pennies, 1 quarter and 1 dime, 1 quarter and 3 nickels, 1 quarter, 1 dime, and 2 pennies, 3 dimes and 1 nickel, or 7 nickels and 2 pennies. In total, there are 5 ways to make 37 cents using different coin combinations.
Bob has 60 coins consisting of quarters and dimes The coins combined value is 9.45 How many are quarters and how many are dimes?
there are 23 quarters 37 dimes to do this use simultaneous equations to make this simpler i will assign variables to amount of quarters and dimes x-quarters y-dimes you know you have 60 coins, so amount of quarters plus dimes is 60 x+y=60 you also know the amount is equal to $9.45 since quarters are $0.25 and dimes are $0.10 another equation can be made 0.25x+0.10y=9.45 this equation shows what you do when you count your change now solve the first equation for a variable using algebra x=60-y you can then plug this new value into your second equation 0.25(60-y)+0.1y=9.45 you can now solve for y, which is the number of dimes y=37 now plug this number back into x=60-y to get the amount of quarters x=60-(37) x=23 23 quarters 37 dimes
If Ryan has 6 quarters 3 dimes 2 nickels and 4 pennies how many different sets of coins could he use to make 1.50?
Depends on your definition of "Sets of Coins"if this means combinations of units of currency the answer is Two (2):1) 6 quarters = 1.502) 5 quarters, 2 dimes, and 1 nickel = 1.50if each individual coin is treated as a unique item then option 2 becomes 36 different options:6 different quarters could be excluded3 different dimes could be excluded2 different nickels could be excludedfor 6x3x2 = 36 combinations +1 (the 6 quarter method)=37 sets of coins.
