5/7 divided by 7/5 = 25/49= 5/7÷7/5=5/7 *5/7= 25/49
Haiku: 5/7/5 tanka: 5/7/5/7/7
5/7 divided by 5 = 5/7 * 1/5 = 5/(7*5) = 5/35 = 1/7
5 out of 7 = 5/7 = 5 divided by 7 = 0.714286
5 - (40/7) = - 5/7(5 - 40)/7 = -5
11/3 because it is comprime
736 and 21 are comprime so the fraction cannot be reduced.
5 syllables 7 syllables 5 syllables 7 syllables 7 syllables 5-7-5-7-7 5 syllables 7 syllables 5 syllables 7 syllables 7 syllables 5-7-5-7-7 5 syllables 7 syllables 5 syllables 7 syllables 7 syllables 5-7-5-7-7
5/7 divided by 7/5 = 25/49= 5/7÷7/5=5/7 *5/7= 25/49
Haiku: 5/7/5 tanka: 5/7/5/7/7
G:--------------: d:--------------: a:-4-5-6-7------: e:---------7-0--: g:--------------------5-4----------------------------: d:----------4-5----4-5------5-9-8~-----7-5-----------: a:-4-5-6-7------6-7-------7--------------7-5-7-------:- e:---------------------------------------------------: g:---------------------5-4-----7-5--: d:---------4-5-----4-5-------5------: a:-4-5-6-7-----6-7---------7--------: e:----------------------------------: g:---------9-7--------------------------------: d:--------------9-7-5---8-7-8-7-8-7-5---------: a:-4-5-6-7------------7----------------7-5-7--: e:--------------------------------------------:
5/7 divided by 5 = 5/7 * 1/5 = 5/(7*5) = 5/35 = 1/7
5+6+7 , 5+7+6 , 6+5+7, 6+7+5 , 7+5+6, and 7+6+5
5 out of 7 = 5/7 = 5 divided by 7 = 0.714286
Look at the powers of 5 mod 7: 5¹ mod 7 = 5 5² mod 7 = 5 × (5¹ mod 7) mod 7 = (5 × 5) mode 7 = 25 mod 7 = 4 5³ mod 7 = 5 × (5² mod 7) mod 7 = (5 × 4) mod 7 = 20 mod 7 = 6 5⁴ mod 7 = 5 × (5³ mod 7) mod 7 = (5 × 6) mod 7 = 30 mod 7 = 2 5⁵ mod 7 = 5 × (5⁴ mod 7) mod 7 = (5 × 2) mod 7 = 10 mod 7 = 3 5⁶ mod 7 = 5 × (5⁵ mod 7) mod 7 = (5 × 3) mod 7 = 15 mod 7 = 1 5⁷ mod 7 = 5 × (5⁶ mod 7) mod 7 = (5 × 1) mod 7 = 5 mod 7 = 5 At this point, it is obvious that the remainders will repeat the cycle {5, 4, 6, 2, 3, 1} There are 6 remainders in the cycle, so the remainder of 30 divided by 6 will tell you which remainder to use; if the remainder is 0, use the 6th element. 30 ÷ 6 = 5 r 0 →use the 6th element which is 1, so 5³⁰ ÷ 7 will have a remainder of 1. 1 ≡ 5³⁰ mod 7.
7+5=12 5+7=12 12-5=7 12-7=5
5/7 is the answer. 5/7 X 7 = 5.