No, because 8 isn't a factor of 30.
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
Yes, it is.
Yes, they are a simple multiple of the Pythagorean Triple 5-12-13
Area = 1/2*8*12*sin150 = 24 square units
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.
A triangle can't have sides with lengths of 12, 12, and 24. Well, maybe you might call it a 'degenerate' triangle', with angles of 0°, 0°, and 180°. The two sides of 12 and 12 together are just exactly long enough to reach from one end of the 24 to the other, so they flop down and lie right on top of it. When you look at this 'triangle', it looks like a single line with a length of 24.
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
first find half of base which is 12 and then you add 18,18 and 24 for the 3 sides the result is 60 then divide 60 by 12 which is 5 that is your answer.
Yes, it is.
If a triangle with a perimeter of 24 cm is an equilateral triangle, then each of its 3 sides will be 8 cm in length
It's half the size of a quadrilateral with 24 square units ------------ One type of triangle with an area of 12 square units is the isosceles triangle with two 5-unit sides and one 6-unit side.
24
Yes, they are a simple multiple of the Pythagorean Triple 5-12-13
Area = 1/2*8*12*sin150 = 24 square units
This is merely a doubling of the 5-12-13 triangle. The sides are 10 and 24 ft.
the measure of the base in the similar triangle would be 24 inches because you are increasing by a scale factor of (3/1)
8cm !