A circle has infinite lines of symmetry, all passing through the center. A square has four lines of symmetry: top to bottom, left to right, and the two diagonals.
not all shapes have lines of symmetry. one example is a triangle.
All regular octagons have the same number of lines of symmetry, but octagons with unequal sides would have fewer lines of symmetry.
no, only equilateral triangles have 3 lines of symmetry
All trapeziums have no lines of symmetry unless it is an isosceles trapezium which has one line of symmetry
A circle has infinite lines of symmetry, all passing through the center. A square has four lines of symmetry: top to bottom, left to right, and the two diagonals.
The diagonals of a rectangle aren't lines of symmetry unless it's square.
A quadrilateral with 4 right angles can only be a rectangle or a square. A rectangle has only two lines of symmetry - the lines joining the midpoints of its opposite sides. So the answer cannot be a rectangle. A square has the same lines of symmetry as a rectangle, plus the two diagonals - 4 lines in all.
not all shapes have lines of symmetry. one example is a triangle.
rhombus has all sides equal and diagonals also bisect each other hence it has line of symmerty
yes they are i of cause know all about math
The square is the only one I can think of. The lines are vertical, horizontal, and both diagonals.
All regular octagons have the same number of lines of symmetry, but octagons with unequal sides would have fewer lines of symmetry.
Not all 4 sided quadrilaterals have lines of symmetry although some of them do have lines of symmetry.
no, only equilateral triangles have 3 lines of symmetry
All trapeziums have no lines of symmetry unless it is an isosceles trapezium which has one line of symmetry
First of all, your grammar is terrible. The question should be "Does a triangle have 2 lines of symmetry and 2 lines of rotational symmetry? and the answer is no. A triangle can not have 2 lines of rotational symmetry, because you only rotate the image, you do not use any lines.