All multiples of 6 have 3 as a factor
They are all multiples of 6
42 is the LCM of 3, 6 and 7. All multiples of 42 are multiples of 3, 6 and 7
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
They are the multiples of 6. Since there are infinitely many of them I will not even attempt to list all of them.
Oh, dude, like, totally! If a number is a multiple of 6, it means it can be divided evenly by 6, right? And since 6 is just 3 times 2, any number that's a multiple of 6 is also a multiple of 3. It's like getting two for the price of one, man.
Because 3 is a factor of 6.
Yes, but not all of them. Every multiple of 6 is also a multiple of 3, but there are more multiples of 3 besides those.
Since 2 is a multiple of 6, all multiples of 6 are also multiples of 2.
Because 6 is a multiple of 3.
3 yes, 6 no.
All the multiples of 24 are also multiples of 6.
0 The positive multiples are: 6, 12, 18 & 24. Also, all the negative multiples of 6!
Multiples of 6 must also be multiples of 1, 2 and 3.
All multiples of 6 have 3 as a factor
Yes (12,18,24,30,36 etc)
18 and all the multiples of 18.