All common multiples of 7, 10 and 8 are divisible by them. The lowest common multiple of them is 280, so all multiples of 280 are divisible by them, namely 280, 560, 840, 1120, ...
Any multiples of 7 are divisible by 7
Because they are multiples of 5. All multiples of 5 have 5 as a factor, which means they are divisible by 5.
15735
All of its multiples are.
All multiples of 7, which is an infinite number.
All multiples of 663, which is an infinite number.
35 and all its multiples.
All common multiples of 7, 10 and 8 are divisible by them. The lowest common multiple of them is 280, so all multiples of 280 are divisible by them, namely 280, 560, 840, 1120, ...
Any multiple of 7 is divisible by 7. The integers are of the form I = 7n for any integer n.The number 7 and all numbers that are multiples of 7.
All multiples of 18 are divisible by 9. Not all multiples of 9 are divisible by 18.
Itself and any of its multiples
Any multiples of 7 itself
Any multiples of 7 are divisible by 7
7 is only divisible by itself and one because it is a prime number.
yes since 9 is divisible by 3 all its multiples are as well
Because they are multiples of 5. All multiples of 5 have 5 as a factor, which means they are divisible by 5.