Depends if you are talking about divisible with whole numbers then no. For example 60/20=3 and 60/40=1.5.
40 is divisible by 1, 2, 4, 5, 8, 10, 20, 40.
No number between 20 and 40 is divisible by all 4 numbers. The smallest number divisible by all 4 of those numbers is: 56
24, 30 and 36.
20 and 40
Any element of the set of numbers of the form 40*k, where k is an integer, is evenly divisible.
40 is divisible by 1, 2, 4, 5, 8, 10, 20, 40.
The numbers 20 and 40 are both multiples of 10, as they can be divided evenly by 10. They are also both even numbers, ending in 0. Additionally, both numbers are divisible by 5, as they end in 0.
No number between 20 and 40 is divisible by all 4 numbers. The smallest number divisible by all 4 of those numbers is: 56
Well, honey, numbers that are divisible by 4 and 5 are simply multiples of their least common multiple, which is 20. So, any number that can be divided by both 4 and 5 without a remainder is fair game. Just think of it as the love child of 4 and 5, born to make your math problems a little less complicated.
24, 30 and 36.
20 and 40
Any element of the set of numbers of the form 40*k, where k is an integer, is evenly divisible.
10, 20, 30, 40, 50
1234568 10 12 20 30 40 60
80 is an even number, thus it is divisible by 2; 80/2 = 40. 40 is also even, so it too is divisible by 2; 40/2 = 20. The same applies to 20; 20/2 = 10, and to 10; 10/2 = 5. Since both 2 and 5 are prime numbers, the prime factorization of 80 is 24 X 5.
The divisors of 40: 1 | 2 | 4 | 5 | 8 | 10 | 20 | 40 (8 divisors)
All multiples of 20, which is an infinite number. The first 5 numbers are: 20, 40, 60, 80, 100.