Yes.
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NO, it is not divisible by all numbers. This is easy to see if you remember that 27 is an odd number and odd numbers are NOT divisible by 2. Then there is the issue that is is NOT divisible by any number greater than itself. That is a lots of numbers that don't work!
Check if a number is divisible by 2. Then check divisibility by all odd numbers, up to the square root of the number. If it isn't divisible by any of those, your number is a prime number. For higher numbers, this method may be very slow - but you asked for EASY methods, and the faster methods are certainly not easy.
The number 945 is divisible by 3,7,5 and 9. An easy way to determine what number is divisible by a set of numbers is to multiply all the numbers in the set.3*9*7*5=945 The LCM is 315.
For 4:Are the last two digits in your number divisible by 4? If so, the number is too! For example: 358912 ends in 12 which is divisible by 4, thus so is 358912. For 6: The number must be divisible by 2 and 3. For 8: This one's not as easy, if the last 3 digits are divisible by 8, so is the entire number. Example: 6008 - The last 3 digits are divisible by 8, therefore, so is 6008.
It is easy to see if 221 is divisible by 6. The number 6 is even and 221 is not. An even number cannot evenly divide an odd number . You get: 36.8333333... recurring A handy rule is: Any number is divisible by 6 if it is divisible by both 2 and 3.