Yes, the set of odd integers is closed under multiplication. When you multiply two odd integers, the product is always odd. For example, multiplying 3 (odd) by 5 (odd) results in 15, which is also odd. Thus, the product of any two odd integers remains within the set of odd integers.
1 No. 2 No. 3 Yes.
Yes
No. 1 + 3 = 4, which is not odd. In fact, no pair of odds sums to an odd. So the set is not closed under addition.
Let + (addition) be a binary operation on the set of odd numbers S. The set S is closed under + if for all a, b ϵ S, we also have a + b ϵ S. Let 3, 5 ϵ the set of odd numbers 3 + 5 = 8 (8 is not an odd number) Since 3 + 5 = 8 is not an element of the set of the odd numbers, the set of the odd numbers is not closed under addition.
Yes, the set of odd integers is closed under multiplication. When you multiply two odd integers, the product is always odd. For example, multiplying 3 (odd) by 5 (odd) results in 15, which is also odd. Thus, the product of any two odd integers remains within the set of odd integers.
The numbers are not closed under addition because whole numbers, even integers, and natural numbers are closed.
1 No. 2 No. 3 Yes.
That is correct, the set is not closed.
Yes
addition
No. 1 + 3 = 4, which is not odd. In fact, no pair of odds sums to an odd. So the set is not closed under addition.
Because the set is not closed under addition. If x and y are odd, then x + y is not odd.
No. For example, 5 is an odd integer and 3 is an odd integer, yet 5/3 is neither an integer nor odd (as odd numbers are, by definition, integers).
Yes.To say a set is closed under multiplication means that if you multiply any 2 numbers in the set, the answer will always be a member of the set. When you multiply 2 odd numbers, the answer is always an odd number, so the set is closed.It must be the same person asking these questions!Read more: Is_the_set_of_odd_integers_closed_under_subtraction
Let + (addition) be a binary operation on the set of odd numbers S. The set S is closed under + if for all a, b ϵ S, we also have a + b ϵ S. Let 3, 5 ϵ the set of odd numbers 3 + 5 = 8 (8 is not an odd number) Since 3 + 5 = 8 is not an element of the set of the odd numbers, the set of the odd numbers is not closed under addition.
Suppose m and n are integers. Then 2m + 1 and 2n +1 are odd integers.(2m + 1)*(2n + 1) = 4mn + 2m + 2n + 1 = 2*(2mn + m + n) + 1 Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + m + n is an integer - say k. Then the product is 2k + 1 where k is an integer. That is, the product is an odd number.