Is the set of negative interferes a group under addition? Explain,
Yes it is.
Yes.
If you mean the set of non-negative integers ("whole numbers" is a bit ambiguous in this sense), it is closed under addition and multiplication. If you mean "integers", the set is closed under addition, subtraction, multiplication.
No. It is not a group.
Is the set of negative interferes a group under addition? Explain,
Yes it is.
no
addition
That is correct, the set is not closed.
Yes.
If you mean the set of non-negative integers ("whole numbers" is a bit ambiguous in this sense), it is closed under addition and multiplication. If you mean "integers", the set is closed under addition, subtraction, multiplication.
Because the set is not closed under addition. If x and y are odd, then x + y is not odd.
No. It is not a group.
You don't say that "an integer is closed". It is the SET of integers which is closed UNDER A SPECIFIC OPERATION. For example, the SET of integers is closed under the operations of addition and multiplication. That means that an addition of two members of the set (two integers in this case) will again give you a member of the set (an integer in this case).
The set of positive integers does not contain the additive inverses of all but the identity. It is, therefore, not a group.
It provides closure under the binary operation of addition.