It can have.
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
The adjacent sidesof a rhombus are always congruent... that's one of the identifying factors. A rhombus has all sides congruent, opposite sides parallel, and bisecting diagonals.
No. The diagonals of rhombus are not equal.
There are 2
Only a square and a rhombus will have all its diagonals bisecting vertices. In other shapes some - but not all - diagonals can bisect vertices.
It can have.
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
The adjacent sidesof a rhombus are always congruent... that's one of the identifying factors. A rhombus has all sides congruent, opposite sides parallel, and bisecting diagonals.
Not in general.
Always. In fact, one method of proving a quadrilateral a rhombus is by first proving it a parallelogram, and then proving two consecutive sides congruent, diagonals bisecting verticies, etc.
Yes, the diagonals of a rhombus are perpendicular.
No. The diagonals of rhombus are not equal.
No. The diagonals of rhombus are not equal.
There are 2
By definition, a rhombus is a parallelogram with all its sides equal in length and is symmetrical about each of its diagonals..A square is a rectangle with all its sides equal in length and is symmetrical about its diagonals and the axes perpendicularly bisecting each pair of opposite sides.Consequently, a square can never be a rhombus but it could be argued that a rhombus whose vertex angles all become 90° then becomes a square.
No. The diagonals of rhombus are not equal.