5 is.
As a product of its prime numbers: 5*5*5 = 125
To express 250 as a product of its prime factors, we start by dividing it by the smallest prime number, which is 2. This gives us 250 ÷ 2 = 125. Next, we factor 125, which is 5 × 25, and since 25 can be further factored into 5 × 5, we have 125 = 5^3. Therefore, the prime factorization of 250 is 2 × 5^3.
250 has only two prime factors and as a product if its prime factors: 2*5*5*5 = 250
5*5*5 = 125
As a product of its prime factors: 5*5*5 = 125
1, 2, 5, 10, 25, 50, 125, 250 2 and 5 are prime.
The factors of 250 are: 1 2 5 10 25 50 125 250 The prime factors are: 2 x 5 x 5 x 5
As a product of its prime numbers: 5*5*5 = 125
To find two numbers that multiply to 250, we need to factorize 250. The prime factorization of 250 is 2 x 5^3. Therefore, the two numbers that multiply to 250 are 2 and 125, as 2 x 125 = 250.
The prime numbers (factors) of 250 are: 2 and 5
The prime factors of 250 are 2 and 5.
No. Other than 5, no prime numbers end in 5.
250 has only two prime factors and as a product if its prime factors: 2*5*5*5 = 250
5*5*5 = 125
As a product of its prime factors: 5*5*5 = 125
1 x 250, 2 x 125, 5 x 50, 10 x 25 and 125 + 125 = 250
There can only be 3 of them because as a product of its prime factors: 5*5*5 = 125