it already was made search it up on wikipedia.org
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They are not!
Subtract the powers. e.f. 2^(3 ) divide 2^(5) = 2^(3 - 5) = 2^(-2)
2 for linear (powers of 1), 3 for quadratic (powers of 2), etc
No. All powers of 2 will be greater than zero.
Your example is confusing -- while 2^4 = 4^2, in general it is false that x^y=y^x, so not sure what you mean by "converting powers." A relevant rule is that (a^b)^c = a^(bc) (power of a power is product of powers) If a=2, b=2, and c=2 then a^b = 2-squared = 4 and the formula gives 4^2 = 2^(2*2) which is true. Also (a^b)*(a^c) = a^(b+c) (multiply numbers, add powers) and (a^b)/(a^c) = a^(b-c) (divide numbers, subtract powers)