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To find the probability of a randomly selected woman having a height within a specific range, we can use the normal distribution with the given mean (μ = 63.6 inches) and standard deviation (σ = 2.1 inches). For instance, if we want to find the probability that a randomly selected woman is shorter than 65 inches, we would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the height in question. After calculating the z-score, we would consult the standard normal distribution table or use a calculator to find the corresponding probability. If you have a specific height range in mind, please specify for a more detailed calculation.
What else can I help you with?
A bank and loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected find the probabili?
To find the probability of a randomly selected applicant receiving a credit rating above a certain value, you would first need to determine that value. For example, if you want to find the probability of an applicant having a rating above 250, you would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the rating, ( \mu ) is the mean (200), and ( \sigma ) is the standard deviation (50). After calculating the z-score, you can use the standard normal distribution table or a calculator to find the corresponding probability.
What conditions are necessary in order to use a t-test to test the differences between two population means?
The samples must be randomly selected, independent, and normally distributed. The following are necessary to use a t-test for small independent samples. 1. The samples must be randomly selected. 2. The samples must be independent. 3. Each population must have a normal distribution.
For a sample of 140 randomly selected patients the mean amount spent was 86.50 and the standard deviation was 11.45. What is a 95 percent confidence interval for the mean?
sample size, n = 140standard deviation, s = 11.45standard error of the mean, SE = s / n^1/2 = 11.45 / 140^1.2 = 0.967795% confidence interval => mean +- 1.96SE95% CI = 86.5 - 1.96*0.9677; 86.5 + 1.96*0.9677= 84.6; 88.4
How do you spell randomly?
That is the correct spelling of the word "randomly" (by chance).
Is the probability of randomly meeting someone born on a Monday?
The probability of randomly meeting someone born on a Monday is approximately 1 in 7, or about 14.3%. This is based on the assumption that births are evenly distributed across the days of the week. However, actual birth rates can vary slightly by day, influenced by factors such as hospital practices and cultural trends. Nonetheless, for a rough estimate, 1 in 7 is a reasonable approximation.
The average amount customers at a certain grocery store spend yearly is 636.55 Assume the variable is normally distributed If the standard deviation is 89.46 find the probability that a randomly?
.820=82.0%
A bank and loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected find the probabili?
To find the probability of a randomly selected applicant receiving a credit rating above a certain value, you would first need to determine that value. For example, if you want to find the probability of an applicant having a rating above 250, you would calculate the z-score using the formula ( z = \frac{(X - \mu)}{\sigma} ), where ( X ) is the rating, ( \mu ) is the mean (200), and ( \sigma ) is the standard deviation (50). After calculating the z-score, you can use the standard normal distribution table or a calculator to find the corresponding probability.
What is the probability that a randomly selected case from a normally distributed distribution will have a score between -1.00 and the mean?
The answer is 0.1586
Are normally distributed with a mean of 68 inches and a standard deviation of 2 inches What is the probability that the height of a randomly selected female college basketball player is more than 66?
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
Galaxies are not distributed randomly but are grouped in?
çlusters
How are spots distributed on the back of your hand?
randomly
What conditions are necessary in order to use a test to test the differences between two population means?
The samples must be randomly selected, independent, and normally distributed. The following are necessary to use a t-test for small independent samples. 1. The samples must be randomly selected. 2. The samples must be independent. 3. Each population must have a normal distribution.
What is the probability that the value of a randomly selected variable from a normal distribution will be more than 3 standard deviation from its mean value?
Approx 0.0027
When grass is randomly distributed throughout an environment a population of deer that eats grass is most likely to have a?
Random Pattern.
According to the plum pudding model electrons are distributed randomly thoughtout the positively charge pudding of the atom?
Atom
Which genetic concept states that chromosomes are distributed to gametes?
The concept of Mendelian segregation states that chromosomes are randomly distributed to gametes during meiosis. This ensures genetic diversity in the offspring.
What conditions are necessary in order to use a t-test to test the differences between two population means?
The samples must be randomly selected, independent, and normally distributed. The following are necessary to use a t-test for small independent samples. 1. The samples must be randomly selected. 2. The samples must be independent. 3. Each population must have a normal distribution.
