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∙ 15y agoA vehicle that is traveling at 94 km/hr travels west from 1:00 p.m. to 3:30 p.m. That's 2 and 1/2 hours of travel time at 94 km/hr. The car will travel 94 km/hr times 2 1/2 hr or 235 km in the time specified. That means the car will be that much farther west than it was at the start, which was 17 km west of a school. Add the distance from the school to the starting point of the vehicle and you'll know where the car will be at the end of the observation period. 235 km + 17 km = 252 km west of the school.
Wiki User
∙ 15y ago99.7 km/hr
Another car would have to travel at 70 km/hr west.To have the same velocity, it must have the same speed toward the same direction.
If you increase the rate of which the projectile was once traveling toward your opponent. A good hard return chap.
If the person sat on the train their velocity relative to the ground would be 95kph. But he/she is goind 3kph to oppose this. So 95-3 = 92 kph to the north is velocity of person relative to the ground.
0.333333333 Recuring metres a second
99.7 km/hr
The velocity of a falling object increases as it falls due to the acceleration of gravity acting on it. As the object falls, it gains speed and accelerates toward the ground until it reaches a constant velocity known as terminal velocity.
No. The cyclist is moving at a constant speed, but her velocity is changing. Remember that velocity is speed with a direction vector associated with it. As speed is constant, only direction is changing. But a change in direction is a change in velocity (even if speed is constant), and this requires acceleration in that direction to accomplish the change in direction. You're on the right track, but just recall that acceleration is tied to velocity and not just speed. And note that velocity can change all the time without speed changing. Acceleration must cause the change in velocity. Consider that objects in orbit around the earth move at a pretty constant speed, but accelerate toward the earth all the time. Their speed coupled with their acceleration toward earth cause them to move in an arc - which is their orbital path.
Your velocity changes because velocity is a vector quantity that includes both speed and direction. When you ride a Ferris wheel, your direction changes as you move up and down, even though the wheel turns at a constant speed. This change in direction causes a change in your velocity.
The car is accelerating because its direction is changing due to the curve. Although the speed may be constant, the car is undergoing centripetal acceleration toward the center of the curve to maintain its path.
Another car would have to travel at 70 km/hr west.To have the same velocity, it must have the same speed toward the same direction.
If the path is perfectly circular, yes, the speed is constant. This should not be confused with the velocity, because while speed is constant, its direction is not; therefore velocity is always changing.
Objects change velocity as they move toward Earth at a rate of 9.8 m/s^2 due to the acceleration caused by gravity. This acceleration is a result of the gravitational force between the object and Earth, causing the object to accelerate towards the Earth's center at a constant rate.
What the answer
Acceleration means any change in either speed or direction of motion.If speed remains constant, there may still be acceleration present if thedirection of the motion is changing.If the rate at which speed and/or direction are changing remains constant,then the acceleration is constant
When kinetic energy is absorbed as an object moves toward the earth, the object's speed decreases as the kinetic energy is converted into other forms, such as potential energy or heat. This decrease in speed continues until the object comes to a stop, usually upon impact with the ground.
Short answer: yes.The force required to maintain constant-velocity circular motion is called centripetal force, and it acts toward the center of the circle (perpendicular to the object's tangential velocity). Centripetal force is given byf_c = mv^2 / rwhere m is the mass of the orbiting object, v is its tangential velocity and r is its (presumably constant) distance from the center of rotation. Centripetal acceleration is given by dividing both sides of this equation by m (as governed by Newton's second law).