At the point (2, 4).
It works out that they intersect at: (4, -7)
x = 3 and y = 2 so the lines intersect at the point (3, 2)
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).
At the point (2, 4).
It works out that they intersect at: (4, -7)
By a process of elimination and substitution the lines intersect at: (4, -7)
By a process of elimination and substitution the lines intersect at: (1/4, 0)
x = 1 and y = 6 so the lines intersect at the point (1, 6)
x = 3 and y = 2 so the lines intersect at the point (3, 2)
x = 2 and y = 1 The lines intersect at the point (2, 1)
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).
Two straight lines that intersect.
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.