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At what point during a pole-vaulters jump is his gravitational potential energy the greatest?
Wiki User
∙ 14y ago
His gravitational potential energy is greatest at the highest point in his vault. Viewing this problem ideally (where all outside factors are discarded), the pole vaulter's jump follows a parabolic path, and the vaulter will obviously be the furthest distance from the earth's surface when he reaches the highest point in the parabolic path and begins his descent. The gravitational potential energy of a single object with respect to the earth is given by U = mgh, where U is the energy given in joules, m is the mass of the object, g is the gravitational acceleration on earth (around 9.81 m/s2 toward the earth), and h is the positive distance from the earth's surface. In this problem, mass and acceleration are constant, since ideally, the only force acting on the vaulter is the force of gravity that will bring him back to the ground. Therefore, U is maximized at the highest point in the vault - the vertex of the parabola, halfway between the origin of his jump and the point where he hits the ground.
Wiki User
∙ 14y ago
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