As a product of its prime factors: 2*2*2*5 = 40 or as 23*5 = 40
There is no such number. If someone claimed that x was such a number then x+2 would be (a) a greater number and (b) a product of 2. So then x could not be such a number.
The product is a^2 + b^2.
The answer to this convoluted question is as follows: The product of prime numbers, for the composite number 64, is 2*2*2*2*2*2 or 26
Rewrite the factors and product. 2*3^2*5 = 3^2*2*5
5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!5*sqrt(2) is one irrational number. 1/sqrt(2) is another irrational number.Their product is 5!
Another whole number.Specifically, it's what you get when you multiply the 2 numbers together.
As a product of its prime factors: 2*2*2*5 = 40 or as 23*5 = 40
There is no such thing as the product of just one number, a product is when 2 or more numbers are multiplied. The product of a number and another number means the answer you get when you multiply the two.
One possible conjecture: The product is always an odd number. Another possible conjecture: The product is always greater than either of them. Another possible conjecture: Both odd numbers are always factors of the product. Another possible conjecture: The product is never a multiple of ' 2 '. Another possible conjecture: The product is always a real, rational number. Another possible conjecture: The product is always an integer.
As the product of its prime factors it is: 2*7*11*13 = 2002
Yes. A product is the result of one number multiplied by another. For example: 5 x -2 = -10 If you multiply two numbers of the same sign (+ positive or - negative), the product will be positive. For example: -5 x -2 = 10 (positive)
The first prime number is 2. The product of 2, since there is no other number by which to multiply it, is 2.
Integers are whole numbers such as: ..., -3, -2, -1, 0, 1, 2, 3, ... Counting numbers are whole numbers such as: 1, 2, 3, 4, ... So the product can be a whole positive number or zero. Example: (-2)(-3)= 6 (-2)(0) = 0
Without knowing what the product is, it will be difficult to help. Presumably, you can tell the difference between even and odd numbers. If you are trying to predict, the product of two evens is even, the product of two odds is odd and the product of an even and an odd is even.
There is no such number. If someone claimed that x was such a number then x+2 would be (a) a greater number and (b) a product of 2. So then x could not be such a number.
No. The easiest counter-example to show that the product of two irrational numbers can be a rational number is that the product of √2 and √2 is 2. Likewise, the cube root of 2 is also an irrational number, but the product of 3√2, 3√2 and 3√2 is 2.