4 goes into 36 evenly, but 13 does not.
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36/117 = (4×9)/(13×9) = 4/13
Yes because 9 x 4 = 36
Yes because 9 times 4 is 36
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4 & 9 For any two unknown numbers, we can say nm = 36 n + m = 13 Hence n = 13 - m Substitute (13 - m) m = 36 Multiply out 13m - m^2 = 36 m^2 - 13m + 36 = 0 factor ( m -9)( m - 4) = 0 Hence m = 4 & m = 9 NB THis is good for any two unknown numbers, to be found against any constant.