0
What else can I help you with?
Continue Learning about Math & Arithmetic
Related Questions
How do you simplify 47 over 40?
1 and 7/47
Simplify 28 over 40?
It is 7 over 10, which is 0.7 or 70%.
Can you simplify 13 over 40?
no
Can you simplify 11 over 40?
No
How do you simplify 40 over 25?
8 over 5
What is the simplest form of 35 over 40?
The simplest form of 35/40 is 7/8. You just divide the 35 and the 40 by 5. Hope I helped :-)
What is 160 over 280 simplified to?
To simplify the fraction 160 over 280, you can divide both the numerator and the denominator by their greatest common divisor, which is 40. Dividing both by 40 gives you 4 over 7. Therefore, 160 over 280 simplified is 4/7.
Can you simplify 5 over 40?
1/8
How do you simplify 6 over 40?
3/20
Can you simplify 3 over 40?
No, it is already simplified.
Can you simplify 108 over 160?
It simplifies to 27 over 40.
How do you simplify 40 over 3?
40/3 = 13 and 1/3
Trending Questions
What is the name of the letter that represents the unknown?
Which one is heavyer 7.47kg or 7399g?
How far would you travel if you walked 3 miles per hour for 2 hours?
How do you draw iso-profit lines?
Is 54 to 81 in its simplest form?
Is y equals negative 7 plus 6x?
What is the area of the section of land in square feet if 1 mile is 5280?
What is the GCF of 66 and 55?
What is 5 percent out of 100?
What are some 39 clue card codes?
How many hours between 7AM to 3PM?
What polygon family has angle measures that add up to 360?
What is x if the sin of x equals square root of 5 divided by 2?
What is its hundreds place 4578?
Is 12 quarts less than 26 pints?
What are the practical application of linear differential equations?
What careers use the mathematical formula for volume?
1600 mg equals how many grams?
How many meters are in two and three fourths?
What is the date of good Friday 2009?
Copyright ©2025 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.