Yes, it should function. the only problem being the power output which will be slightly less or the consumption greater. The only possible problem being if it is an electronicly controlled one, then a "guard dog" system may stop the heater from working. Guard dog is a system which stops systems from operating at a too low voltage as this may cause regulation problems .
Power= voltage X currant so for the same power output the heater will have to consume more amps (or the power will diminish in proportion to the voltage drop).
CCVIII C = 100 V= 5 III = 3
D=M/V D=240/200 D=1.2 you should include units though. I'm not sure what units you used, which is why i didn't write them.
You mean the formula v = u + at, where v is final velocity, u is starting velocity, a is the rate of acceleration and t is the time taken. Well if a car's acceleration is 20 feet per second per second, in 12 seconds its velocity will have been increased to 20 x 12 = 240 feet per second. So if before it accelerated it was travelling at 100 feet per second, its new speed will be 240 + 100 = 340 feet per second = 340 x 60 x 60 ft per hour = 1224000 ft/hr which is just under 219 mph! Some car!
On a car it is the tube that takes a v-8's 2 exhaust headers and combines them into a a single exhaust to run thru 1 muffler.
To find the average speed you must know the total distance traveled and the total elapsed. The distance traveled in each interval is simply the speed multiplied by the time (v x t). Thus, in the first interval you travel 120 x 1 = 120 meters, in the second interval 120 x 6 = 720 meters; therefore, the total distance traveled is 840 meters. The total time elapsed is 120 + 120 = 240 seconds. An average speed is simply the total distance traveled divided by the total time elapsed thus in this case it is 720 m / 240 s = 3 m/s.
It is not recommended to use 240 volts for a heater that requires 208 volts because this can potentially damage the heater or cause a safety hazard due to overvoltage. It's best to use the voltage specified by the manufacturer for the heater to ensure safe and proper operation.
Yes, a 208 volt 3 phase equipment can work on a 240 volt 3 phase system. The equipment may operate slightly outside of its designed voltage range, so it is important to check the manufacturer's specifications to ensure compatibility and safe operation. A voltage converter may be necessary in some cases.
No, not really. The two hot legs can be opposite legs of a 120/240 V split phase power source. You still do need a protective earth ground, however, but the heater itself does not require a grounded neutral to run.
Yes if it is connected across the lines it will receive 208 volts, which is obviously less than 240 v and the power output would be only three quarters of the rated power.
If you have the right materials than yes it is possible, but i would highly recommend that you protect yourself.
If you have the right materials than yes it is possible, but i would highly recommend that you protect yourself.
Yes, you can connect two 240 V heater elements to a relay rated at 240 V. Make sure that the relay's current rating is sufficient to handle the combined current draw of both heater elements to prevent any overloading or damage. Also, ensure proper wiring and insulation to maintain safety and functionality.
12 amps
VOLTS x (VOLTS/OHMS) = WATTS 240 X (240/8) = 7200 Watts = 7.2KWatts
A 208 v three-phase system has 120 v between each live wire and the neutral. It is used in the USA as an alternative to the 120/240 v single-phase system, offering 50% more power for the same current.
If it is a 240 v delta motor it needs a 240 v three-phase supply, which has 139 v between line and neutral, so 440 v would not be acceptable.
Current (Amps) = Power (Watt)/Voltage (V) Therefore a 4500W heating element will draw 18.75A = 4500W/240V