any tile size up to 12X12 will do
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Length . . . any multiple of 15' Width . . . . any multiple of 15'
In practice you will use more tiles than the equivalent area of the room. A 15 foot strip of tiles will require 15 times 12/13 = 13.846 tiles to cover it. This will have to be rounded to 14 tiles. That means that the 15 foot by 15 foot room will require 14 times 14 tiles = 196 tiles to cover it. And that's if you don't drop and break any or mess up one or more cuts.
Let g= no green tiles and r = no of red tiles At beginning r + g = 15 At end r = g - 2 Add back the 5 red tiles and then r = g -2 + 5 = g - 3 Substituting g-3 for r in original then g-3 + g = 15 2g = 12 g= 6 r= 15 - g = 15 - 6 = 9 No of red tiles = 9; green tiles = 6
If this is for an actual tiling job, the answer is 225. First, convert feet into inches. 1 foot = 12 inches. 24 * 12 = 288 inches So your garage is 288 inches by 288 inches. 288 inches / 19.5 inches = 14.77 So you would need 14.77 tiles across and 14.77 tiles deep. Since you are buying whole tiles, you have to round up. So it would be 15 tiles x 15 tiles. 15 * 15 = 225 tiles. Since many of the tiles have to be cut (0.77 of a tile), it is possible to use the other (0.23) as part of the flooring and get away with a few less tiles, but that's not practical in a real tiling job. It would look terrible.
Whom ever wrote this problem, did not give the unit of measurement (yards, feet, meters, etc.) so, I am going to presume that the 12 by 12 tile is in inches, and the 15 by 15 is in feet. If my presumption was correct the answer is 15 tiles. Because a 12 by 12 tile is = to 1 square foot. How many 1's fit into 15? 15! Well, not exactly..... You need to multiply 15 X 15 to get the square footage and that will give you the number of tiles needed since the tiles are 1 ft square. 15 x 15= 225. So you need 225 tiles. And add extra tiles for breakage...