A pentagonal prism has 7 faces, 10 vertices and 15 edges.
A pentagonal dipyramid (or bipyramid) has 15 edges, 10 faces and 7 vertices.
faces= seven edges=fifteen vertices=ten
I believe you intend to talk about a polyhedron if it is a convex polyhedron, there is a relation : F + V * E = 2 (you can experiment with current polyhedrons) the relation is not satisfied by your numbers
6 faces 10 vertices 15 edges
The Euler characteristic requires that Vertices + Faces = Edges + 2 Here that would require 6 + 7 = 15 + 2 or 13 = 17 which is clearly not true. So there cannot be a polyhedron with the stated configuration.
No. The numbers are not consistent with the requirements of the Euler characteristic.
7 faces. 10 vertices. 15 edges.
A pentagonal prism has 7 faces, 10 vertices and 15 edges.
It has 7 faces, 10 vertices, and 15 edges
Faces: 7 Vertices: 10 Edges: 15
It has 7 faces, 15 edges and 10 vertices
A decahedron is a polyhedron with 10 faces. There are several versions of a decahedron, but none of these are regular. By definition, they all have 10 faces. There is the octagonal prism - with 24 edges and 16 vertices, the square anti-prism, with 16 edges and 8 vertices, the square cupola, with 20 edges and 12 vertices, the pentagonal bi-pyramid, with 15 edges and 7 vertices and the augmented pentagonal prism, with 19 edges and 11 vertices. See, for example, http://en.wikipedia.org/wiki/Decahedron
A heptahedron has 7 faces. It can have 6 vertices and 11 edges, or7 vertices and 12 edges, or8 vertices and 13 edges, or9 vertices and 14 edges, or10 vertices and 15 edges.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 7 faces, 15 edges, 10 vertices
Faces: 7Edges: 15 Vertices: 10
Pentagonal (not pentaginal). 7 faces 15 edges 10 vertices