Yes, a quadrilateral ABCD can be a parallelogram if angle D plus angle B equals 180 degrees. In a parallelogram, opposite angles are equal, and consecutive angles are supplementary (their sum equals 180 degrees). Therefore, if angle D and angle B are supplementary, it is consistent with the properties of a parallelogram. Thus, the condition does not contradict the definition of a parallelogram.
If you mean quadrilateral ABCD then by using the cosine rule diagonal AC equals 5.71 cm and diagonal BD equals 6.08 cm both rounded to two decimal places.
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
A quadrilateral is a parallelogram if one pair of opposite sides are equal and parallel Let ABCD be a quadrilateral in which ABCD and AB=CD, where means parallel to. Construct line AC and create triangles ABC and ADC. Now, in triangles ABC and ADC, AB=CD (given) AC = AC (common side) Angle BAC=Angle ACD (corresponding parts of corresponding triangles or CPCTC) Triangle ABC is congruent to triangle CDA by Side Angle Side Angle BCA =Angle DAC by CPCTC And since these are alternate angles, ADBC. Thus in the quadrilateral ABCD, ABCD and ADBC. We conclude ABCD is a parallelogram. var content_characters_counter = '1032';
No; it is false. The sum of all the angles of a quadrilateral always equals 360o.
9 degrees
never
never
none of these answers are correct
none of these are correct
280
If you mean quadrilateral ABCD then by using the cosine rule diagonal AC equals 5.71 cm and diagonal BD equals 6.08 cm both rounded to two decimal places.
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160 degrees.
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q
A = C = 180 - B = 80 So A + C = 160
A quadrilateral is a parallelogram if one pair of opposite sides are equal and parallel Let ABCD be a quadrilateral in which ABCD and AB=CD, where means parallel to. Construct line AC and create triangles ABC and ADC. Now, in triangles ABC and ADC, AB=CD (given) AC = AC (common side) Angle BAC=Angle ACD (corresponding parts of corresponding triangles or CPCTC) Triangle ABC is congruent to triangle CDA by Side Angle Side Angle BCA =Angle DAC by CPCTC And since these are alternate angles, ADBC. Thus in the quadrilateral ABCD, ABCD and ADBC. We conclude ABCD is a parallelogram. var content_characters_counter = '1032';
for a+ NEVERIn a parallelogram opposite angles are equal. Thus angle c = angle a = 40o.The sum of all the angles in a quadrilateral is 360o, so:angle a + angle b + angle c + angle d = 360o=> 40o + angle b + 40o + angle d = 360o=> angle b + angle d = 280o.