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Yes, a quadrilateral ABCD can be a parallelogram if angle D plus angle B equals 180 degrees. In a parallelogram, opposite angles are equal, and consecutive angles are supplementary (their sum equals 180 degrees). Therefore, if angle D and angle B are supplementary, it is consistent with the properties of a parallelogram. Thus, the condition does not contradict the definition of a parallelogram.

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Abcd is a quadrilateral angle a equals 40 degrees and angle b equals 150 degrees could abcd be a trapezoid?

never


Abcd is a quadrilateral in which angle a equals 40 degrees and angle b equals 150 degrees could abcd be a parallelogram?

never


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Quadrilateral ABCD is a parallelogram in which angle A equals 40 degrees?

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Quadrilateral abcd is a parallelogram in which angle a equals 40 degrees b plus d equals degrees?

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Quadrilateral abcd is a parallelogram in which b equals 100 degrees.a plus c equals?

160 degrees.


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If quadrilateral ABCD is a parallelogram in which angle B equals 100 degrees how many degrees would be a plus c?

A = C = 180 - B = 80 So A + C = 160


A quadrilateral is a parallelogram if a pair of opposite sides is equal and parallel prove?

A quadrilateral is a parallelogram if one pair of opposite sides are equal and parallel Let ABCD be a quadrilateral in which ABCD and AB=CD, where means parallel to. Construct line AC and create triangles ABC and ADC. Now, in triangles ABC and ADC, AB=CD (given) AC = AC (common side) Angle BAC=Angle ACD (corresponding parts of corresponding triangles or CPCTC) Triangle ABC is congruent to triangle CDA by Side Angle Side Angle BCA =Angle DAC by CPCTC And since these are alternate angles, ADBC. Thus in the quadrilateral ABCD, ABCD and ADBC. We conclude ABCD is a parallelogram. var content_characters_counter = '1032';


ABCD is a quadrilateral in which angle A 40 degrees and angle B 150 degrees. Could ABCD be a parallelogram?

for a+ NEVERIn a parallelogram opposite angles are equal. Thus angle c = angle a = 40o.The sum of all the angles in a quadrilateral is 360o, so:angle a + angle b + angle c + angle d = 360o=> 40o + angle b + 40o + angle d = 360o=> angle b + angle d = 280o.