can it for a trapezoid?
24
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
An example of a ratio would be 1:2, say you have two squares, one of the side lengths on the square is 4 inches, the other is 2 the ratio of the smaller rectangle to the larger rectangle is 1 to 2, or 1/2 of the larger rectangle.
28 inches
Yes into 10 inches by 10 inches squares
can it for a trapezoid?
24
It can be any rectangle having a combination of width and length that, when multiplied together, yield a product of 100 squares. The rectangle could be 1 square wide and 100 squares long, or 5 squares wide and 20 squares long, or it could be a plane square with 10 squares wide on each side.
Seven 9 inch squares placed end to end would form a rectangle that was still 9 inches wide but 7 x 9 = 63 inches long. The distance around such a rectangle would measure its perimeter. Two sides are 9 inches long and two sides are 63 inches long. The perimeter would be 63 + 63 + 9 + 9 = 144 inches.
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
If for example the rectangles was 4 inches by 3 inches then by marking out 12 equal one inch squares within the rectangle you'll prove that 4 times 3 = 12 square inches.
Draw a rectangle, two inches by four inches. Draw intersecting lines at 1 inch intervals so that the entire figure is covered by 1 inch squares. There are 8 of them. The area of the rectangle is 8 square inches, or 2 x 4
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
The area of Joseph’s rectangular homework desk is 1,008 square inches. If the length of his desk is 42 inches, how wide is his desk?