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Amoxicillin-clavulanate (amox-clav) 875 mg/125 mg can be used to treat certain types of pneumonia, particularly those caused by susceptible bacteria. However, it is not the first-line treatment for all pneumonia cases. The choice of antibiotic depends on the specific pathogens involved and the patient's health status. It's important to consult a healthcare provider for appropriate diagnosis and treatment recommendations.
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What is 875 over 1000 in simplest form with work showing?
875/125 = 7 1000/125 = 8 875/1000 = 7/8
What is 125 over 875 in simplest form?
125 x 7 = 875 exactly So answer is 1 / 7 or one seventh
What can 875 be divided by?
1, 5, 7, 25, 35, 125, 175, 875
What is 875 out of 1000 simplified?
To simplify the fraction ( \frac{875}{1000} ), we can divide both the numerator and the denominator by their greatest common divisor, which is 125. This results in ( \frac{875 \div 125}{1000 \div 125} = \frac{7}{8} ). Therefore, 875 out of 1000 simplified is ( \frac{7}{8} ).
What is the HCF of 875 and 1000?
The GCF is 125.
What is 875 divided by 7?
125
What is the LCM of 125 and 175?
The least common multiple of 175 and 125 is 875.
What is 875 over 1000 in simplest form with work showing?
875/125 = 7 1000/125 = 8 875/1000 = 7/8
What is 125 divided by 875?
0.1429
What are the factors of 875?
The factors of 875 are 1, 5, 7, 25, 35, 125, 175, and 875.
What are the factor pairs of 875?
875 = 1 x 875 875 = 5 x 175 875 = 7 x 125 875 = 25 x 35
What is 1000 subtract by 125?
875
What is 125 over 875 in simplest form?
125 x 7 = 875 exactly So answer is 1 / 7 or one seventh
What can 875 be divided by?
1, 5, 7, 25, 35, 125, 175, 875
What are the factors for 875?
1, 5, 7, 25, 35, 125, 175, 875
What are factors for 875?
1, 5, 7, 25, 35, 125, 175, 875
What is 875 out of 1000 simplified?
To simplify the fraction ( \frac{875}{1000} ), we can divide both the numerator and the denominator by their greatest common divisor, which is 125. This results in ( \frac{875 \div 125}{1000 \div 125} = \frac{7}{8} ). Therefore, 875 out of 1000 simplified is ( \frac{7}{8} ).
